有没有办法解析Complex RegEx模式(包含多个named groups
以及多个numbered groups
和non-capturing groups
)并报告每个groupname
或{{1与模式文本一起。
假设我确实有这样的RegEx模式:
groupnumber
我想提取:=
(?im)(?<x>\b[a-s03]+\b)(?-i)(?<a>\p{L}+?,(?<b>.+?:(?<c>.+?;(?<d>.+?(?:\d|sample-text|(\k'x'|sos30))))))
此要求的目的:
我有一个庞大的复杂RegEx模式数据库。之前编写的程序员在准备这些复杂模式时没有使用任何注释[ Named groups:
x==>(?<x>\b[a-s03]+\b)
a==>(?<a>\p{L}+?,(?<b>.+?:(?<c>.+?;(?<d>.+?(?:\d|sample-text|(\k'x'|sos30))))))
b==>(?<b>.+?:(?<c>.+?;(?<d>.+?(?:\d|sample-text|(\k'x'|sos30)))))
c==>(?<c>.+?;(?<d>.+?(?:\d|sample-text|(\k'x'|sos30))))
d==>(?<d>.+?(?:\d|sample-text|(\k'x'|sos30)))
Numbered groups:
1==>(\k'x'|sos30)
Non-capturing-groups:
1st==>(?:\d|sample-text|(\k'x'|sos30))
],而且这些模式中不存在(?#...)
。我必须在某些情况下修改这些模式,并且还必须在这些模式中使用注释。现在它就像在草垛中寻找一根针。我根本无法将RegEx用于此目的。所以,我倾向于在这种情况下使用解析器。
我尝试了什么:
为此,我尝试了linebreaks
和GetGroupNames
集合。我只能提取GetGroupNumbers
的{{1}},而不能提取相应的文字模式。
我正在寻找非RegEx解决方案/一些提示。
答案 0 :(得分:3)
对此如何:
(?im)(?<x>\b[a-s03]+\b)(?-i)(?<a>\p{L}+?,(?<b>.+?:(?'c'.+?;(.+?(?:\d|sample-text|(\k'x'|sos30))))))
这是输出:
(0)<0>: (?im)(?<x>\b[a-s03]+\b)(?-i)(?<a>\p{L}+?,(?<b>.+?:(?'c'.+?;(.+?(?:\d|sample-text|(\k'x'|sos30))))))
(1)<x>: \b[a-s03]+\b
(2)<a>: \p{L}+?,(?<b>.+?:(?'c'.+?;(.+?(?:\d|sample-text|(\k'x'|sos30))))
(3)<b>: .+?:(?'c'.+?;(.+?(?:\d|sample-text|(\k'x'|sos30)))
(4)<c>: .+?;(.+?(?:\d|sample-text|(\k'x'|sos30))
(5)<5>: .+?(?:\d|sample-text|(\k'x'|sos30)
(6)<6>: \k'x'|sos30
这是代码:
Imports System.Collections.Specialized
Module Module1
Public DictGroups As New OrderedDictionary
Public DictTrackers As New Dictionary(Of Integer, Boolean)
Public intGroups As Integer = 0
Public CommandGroup As Boolean = False
Sub Main()
Dim regexToEval As String = "(?im)(?<x>\b[a-s03]+\b)(?-i)(?<a>\p{L}+?,(?<b>.+?:(?'c'.+?;(.+?(?:\d|sample-text|(\k'x'|sos30))))))"
Dim curChar As String = ""
DictGroups.Add(0, "(0)<0>: " & vbTab)
DictTrackers.Add(0, True)
For i = 1 To regexToEval.Length
Dim iChar As String = regexToEval.Substring(i - 1, 1)
If curChar <> "\" AndAlso iChar = ")" Then EndGroup()
AddStrToTrackers(iChar)
If curChar = "\" OrElse iChar <> "(" OrElse regexToEval.Length < i + 2 Then curChar = iChar : Continue For
If regexToEval.Substring(i, 1) = "?" Then
i += 1 : AddStrToTrackers("?")
If regexToEval.Substring(i, 1) = ":" Then i += 1 : AddStrToTrackers(":") : curChar = ":" : Continue For
Dim NameLength As Integer = 0
If regexToEval.Substring(i, 1) = "<" Or regexToEval.Substring(i, 1) = "'" Then
i += 1 : AddStrToTrackers(regexToEval.Substring(i - 1, 1))
i += 1
For x = i To regexToEval.Length
If regexToEval.Substring(x - 1, 1) = ">" Or regexToEval.Substring(x - 1, 1) = "'" Then
NameLength = x - i
Exit For
End If
Next
Else
CommandGroup = True
Continue For
End If
If NameLength > 0 Then
Dim GroupName As String = regexToEval.Substring(i - 1, NameLength)
i += NameLength : curChar = regexToEval.Substring(i - 1, 1) : AddStrToTrackers(GroupName & curChar)
intGroups += 1
DictGroups.Add(intGroups, "(" & DictGroups.Count & ")<" & GroupName & ">: " & vbTab)
DictTrackers.Add(intGroups, True)
Continue For
End If
End If
curChar = iChar
intGroups += 1
DictGroups.Add(intGroups, "(" & DictGroups.Count & ")<" & intGroups.ToString & ">: " & vbTab)
DictTrackers.Add(intGroups, True)
Next
Dim Output As String = MakeOutput()
End Sub
Private Function MakeOutput() As String
Dim retString As String = String.Empty
For i = 0 To DictGroups.Count - 1
retString &= DictGroups(i) & vbCrLf
Next
Return retString
End Function
Public Sub EndGroup()
If CommandGroup Then
CommandGroup = False
Exit Sub
End If
Dim HighestNum As Integer = 0
For Each item In DictTrackers
If Not item.Value Then Continue For
If item.Key > HighestNum Then HighestNum = item.Key
Next
If HighestNum <> 0 Then DictTrackers(HighestNum) = False
End Sub
Public Sub AddStrToTrackers(ByVal addString As String)
For Each item In DictTrackers
If item.Value Then DictGroups(item.Key) &= addString
Next
End Sub
End Module
唯一的区别是我没有捕获非捕获组和功能组。当然,这只是我在10分钟内制作的快速代码。但如果你想要的话,这是一个开始。我使用OrderedDictionary作为Group-Numbers的键。如果您还想在输出中包含非捕获组和功能组,则可以更改该结构。
答案 1 :(得分:0)
System.Text.RegularExpressions命名空间中有一个RegexParser类(内部),您可以使用私有反射调用它。到目前为止,我在我的FxCopContrib项目中使用了sample implementation。