Java:UI线程无法在双线程应用程序中恢复

时间:2012-11-16 09:45:11

标签: java multithreading bluetooth

我目前正在使用两个线程构建Java应用程序:

第一个线程是关于应用程序的UI,以及通过蓝牙线程接收的命令处理。

蓝牙线程是等待机器人连接和处理通信的蓝牙服务器。

截至目前,UI线程处于wait()状态,直到蓝牙线程获得要处理的新消息。

问题是,我可以跟踪来自蓝牙线程的notify / notifyAll调用,但是我的UI没有恢复它的活动。

我现在肯定我误解了管理同步线程的正确方法,但我无法弄清楚我的软件出了什么问题。

以下是用户界面的代码:

package mapper;

import java.awt.BorderLayout;
import java.awt.FlowLayout;
import java.util.ArrayList;

import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.JTable;

public class MapperUI extends JFrame implements Runnable {

private ArrayList<String> messageArray;

public MapperUI(){
        super();        
        build();
        this.setVisible(true);
        new Thread(this).start();
}

private void build(){
    setTitle("SLAM Mapper");
    setSize(600,500);
    setLocationRelativeTo(null);
    setResizable(true);
    setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    setContentPane(buildContentPane());
}   
private JPanel buildContentPane(){
    JPanel main = new JPanel();
    main.setLayout(new BorderLayout());

    //TODO Implements auto-generated map after bluetooth communication
    MapPanel map = new MapPanel();
    main.add(map,BorderLayout.CENTER);

    //TODO This fields will be buildt with stored message
    JTable positions = new JTable(15,2);
    main.add(positions,BorderLayout.EAST);

    JPanel buttonPanel = new JPanel();
    buttonPanel.setLayout(new FlowLayout());

    JButton bouton = new JButton("Start");
    buttonPanel.add(bouton);

    JButton bouton2 = new JButton("Send");
    buttonPanel.add(bouton2);

    main.add(buttonPanel,BorderLayout.SOUTH);

    return main;
}

public synchronized void run(){
    MapperCom bt = new MapperCom();
    while(true){
        try {
            System.out.println("Mapper is Waiting......");
            wait();
            String message = bt.getMessage();
            this.messageArray.add(message);
            bt.setNextCommand(processMessage(message));
            notifyAll();
            System.out.println("Mapper Notify");
            build();
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }   
    }
}

public String processMessage(String message){
    String command = "";
    //TODO Build a response
    command = "fffff\n";
    return command;
}
}

这是bluetoothService:

package mapper;

import java.io.DataInputStream;
import java.io.DataOutputStream;
import java.io.IOException;

import javax.bluetooth.DiscoveryAgent;
import javax.bluetooth.LocalDevice;
import javax.bluetooth.UUID;
import javax.microedition.io.Connector;
import javax.microedition.io.StreamConnection;
import javax.microedition.io.StreamConnectionNotifier;

public class MapperCom extends Thread {
public final UUID uuid = new UUID(                              
        "27012f0c68af4fbf8dbe6bbaf7aa432a", false);
public final String name = "Server";                       
public final String url  =  "btspp://localhost:" + uuid         
                            + ";name=" + name 
                            + ";authenticate=false;encrypt=false;";
private LocalDevice local ;
private StreamConnectionNotifier server ;
private StreamConnection conn ;
private DataInputStream din ;
private DataOutputStream dout ;

private String command;
private String message;

public MapperCom(){
     try {
        this.command = "";
        this.message = "";

        System.out.println("Setting device to be discoverable...");
        local = LocalDevice.getLocalDevice();
        local.setDiscoverable(DiscoveryAgent.GIAC);
        System.out.println("Start advertising service...");

        server = (StreamConnectionNotifier)Connector.open(url);
        System.out.println("Waiting for incoming connection...\n");

        conn = server.acceptAndOpen();
        System.out.println("Client Connected...");
        din = new DataInputStream(conn.openInputStream());
        dout = new DataOutputStream(conn.openOutputStream());

        new Thread(this).start();

        } catch (Exception  e) {
            System.out.println("Exception Occured: " + e.toString());
        }
}

@Override
public synchronized void run(){
    System.out.println("Bluetooth Thread Started");
    while(true){
        try {
            String cmd = "";
            char c;
            System.out.println("Waiting for message");
            while (((c = din.readChar()) > 0) && (c!='\n') ){
                System.out.println("Char received :"+c);
                cmd = cmd + c;
            }

            storeMessage(cmd);

            System.out.println("Bt Notify......");
            notifyAll();
            System.out.println("Bt is Waiting for a command from mapper......");
            wait();
            sendResponse();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
}

public void sendResponse(){
    try {
        dout.writeChars(command);
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

public synchronized String getMessage(){
    return this.message;
}

public synchronized void storeMessage (String data){
    this.message = data;
    System.out.println("Received " + data);
}
public synchronized int setNextCommand (String data){
    int result = -1;
    //TODO Implement proper protocol
    this.command = data;
    System.out.println("Sending " + data);

    return result;
}
}

3 个答案:

答案 0 :(得分:5)

我想当您致电notifyAll()时,会拨打this.notifyAll()。其中没有其他元素在同一个班级中等待。因此,您可以做的是在两个类上共享相同的对象并调用obj.wait()obj.notifyAll()。它会工作。

答案 1 :(得分:1)

以下是一个示例程序。基本上,如果你想使用wait&amp; amp;通知。

package ravi.tutorial.java.threads;

public class TestThreads {

    /**
     * @param args
     */
    public static void main(String[] args) {
        CommonLock commonLock = new CommonLock();
        Thread1 thread1 = new Thread1(commonLock);
        Thread2 thread2 = new Thread2(commonLock);
        thread1.start();
        thread2.start();
    }
}

/*
 * Common monitor lock between both threads, used for communication using wait
 * notify.
 */
class CommonLock {

}

// Extending Thread instead of Runnable as its just a test
class Thread1 extends Thread {

    private CommonLock commonLock;

    public Thread1(CommonLock commonLock) {
        this.commonLock = commonLock;
    }

    public void run() {
        System.out.println("Started thread 1");
        System.out.println("waiting thread 1");
        try {
            // TO wait on commonLock, first need to get lock on commonLock. SO
            // put synchronized block of commonLock.
            synchronized (commonLock) {
                commonLock.wait();
            }

        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        System.out.println("DONE waiting thread 1 as I got notification from THread 2");
    }

}

class Thread2 extends Thread {

    private CommonLock commonLock;

    public Thread2(CommonLock commonLock) {
        this.commonLock = commonLock;
    }

    public void run() {
        System.out.println("Running thread 2");

        try {
            System.out.println("Sleeping thread 2");
            // Just take gap of 2 sec before notifying.
            Thread.sleep(2000);

            // TO notify on commonLock, first need to get lock on commonLock. SO
            // put synchronized block of commonLock.
            synchronized (commonLock) {
                System.out.println("Notifying thread 2");
                commonLock.notifyAll();
            }
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    }

}

答案 2 :(得分:0)

看看这个:Thread tutorial

  
      
  • wait()告诉调用线程放弃监视器并转到
      睡觉直到其他一些线程进入同一个监视器并调用
      notify()。

  •   
  • notify()唤醒调用wait()的第一个线程   同一个对象。

  •   
  • notifyAll()唤醒所有调用wait()的线程   同一个对象。优先级最高的线程将首先运行。

  •   

这是对Java中线程概念的主要误解。