Question

我正在创建一个计算旅行费用的程序。每个段都有成本，要求用户输入每个段的成本，然后输入3个段ID（0-6）。增加3个ID的成本以给出最终价格。

如果用户输入＆gt; = 1，我需要从头开始重复该程序（请参阅最后的评论），我该怎么做？另外，我可以改进我的计划，以及如何改进？

import java.util.Scanner;

public class AssignmentArrays{
    public static void main(String[] args){


      Scanner seg0 = new Scanner(System.in);
      Scanner seg1 = new Scanner(System.in);
      Scanner seg2 = new Scanner(System.in);
      Scanner seg3 = new Scanner(System.in);
      Scanner seg4 = new Scanner(System.in);
      Scanner seg5 = new Scanner(System.in);

      int[] data = new int [6];
      data[0] = 0;
      data[1] = 0;
      data[2] = 0;
      data[3] = 0;
      data[4] = 0;
      data[5] = 0;

      /* Segment values */

        while(data[0] == 0){

            System.out.println("Enter cost for segment 0:");
            data[0] = seg0.nextInt();

            System.out.println("Enter cost for segment 1:");
            data[1] = seg1.nextInt();

            System.out.println("Enter cost for segment 2::");
            data[2] = seg2.nextInt();

            System.out.println("Enter cost for segment 3:");
            data[3] = seg3.nextInt();

            System.out.println("Enter cost for segment 4:");
            data[4] = seg4.nextInt();

            System.out.println("Enter cost for segment 5:");
            data[5] = seg5.nextInt();

           /* Path inputs */

           Scanner node1 = new Scanner(System.in);
           Scanner node2 = new Scanner(System.in);
           Scanner node3 = new Scanner(System.in);

           int node1value;
           int node2value;
           int node3value;
           int pathCost;

           System.out.println("Enter ID of segment 0 of path:");
              node1value = node1.nextInt();

           System.out.println("Enter ID of segment 1 of path:");
              node2value = node2.nextInt();

           System.out.println("Enter ID of segment 2 of path:");
              node3value = node3.nextInt();

          /* Path cost calculation */

          pathCost = data[node1value] + data[node2value] + data[node3value];
              System.out.println("The cost of the trip is: $" + pathCost);

          /* Repeate or end program */

           Scanner end = new Scanner(System.in);

           int userChoice;

           System.out.println("Enter 0 to exit or any other number to evaluate another path:");
              userChoice = end.nextInt();

           if (userChoice == 0){
              System.out.println("The program has ended");
              break;
              }
              else if(userChoice >= 1){
              /* REPEATE ALL OF THE ABOVE HERE */
              }
          }

     }

}

Answer 1

我可能会让这个类更加面向对象。但是，您可以使用以下方法分解代码来简化您的工作：

import java.util.Scanner;

public class AssignmentArrays{

static int[] data = new int [6];

public static void getSegmentIDs() {
   ...
}

pubilc static int getUserMenuChoice() {
   ...
}

public static void main(String[] args){

 int exit = false;

 while(!exit) {
   getSegmentIDs();
   choice = getUserMenuChoice();
   if (choice == 0) exit = true;
 } 

}
}

Answer 2

我会通过这样做将整个事情放入do while语句中：

  String answer ="";
  do {
  Scanner seg0 = new Scanner(System.in);
  Scanner seg1 = new Scanner(System.in);
  Scanner seg2 = new Scanner(System.in);
  YOUR CODE CONTINOUS

  /* Repeate or end program */
  System.out.println("would you like to redo? (Y/N)");
  answer = end.next();
  } while(answer.toLowerCase().contains("y"));

用户输入后重复执行的代码

2 个答案: