我想使用Ksoap2连接到基于dot.net的Web服务和我的Android 4.03设备。
我的问题是，当我调用soap请求时，我得到了这个例外：
11-16 08:35:08.649: W/System.err(6392): java.lang.IllegalArgumentException: size <= 0
11-16 08:35:08.649: W/System.err(6392): at java.io.BufferedInputStream.<init>(BufferedInputStream.java:94)
11-16 08:35:08.649: W/System.err(6392): at org.ksoap2.transport.HttpTransportSE.call(HttpTransportSE.java:226)
11-16 08:35:08.649: W/System.err(6392): at org.ksoap2.transport.HttpTransportSE.call(HttpTransportSE.java:114)
11-16 08:35:08.649: W/System.err(6392): at at.jesenko.eDoc.MainActivity$1.run(MainActivity.java:48)
使用
的代码 final String url = "http://server:9007/DWService?wsdl";
final String NAMESPACE = "http://tempuri.org/";
final String METHOD_NAME ="Login";
final String SOAP_ACTION="http://tempuri.org/Login";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Thread loginThread = new Thread(){
@Override
public void run() {
try {
SoapObject Request = new SoapObject(NAMESPACE, METHOD_NAME);
Request.addProperty("userName", "demo");
Request.addProperty("password", "demo1234");
Request.addProperty("organization", "Peters Engineering");
SoapSerializationEnvelope Envelope = new SoapSerializationEnvelope(
SoapEnvelope.VER12);
Envelope.dotNet=true;
Envelope.setOutputSoapObject(Request);
HttpTransportSE ht = new HttpTransportSE(url);
ht.debug = true;
ht.call(SOAP_ACTION, Envelope);
SoapObject response = (SoapObject) Envelope.getResponse();
final String SessionID = response.getProperty("SessionID").toString();
runOnUiThread(new Runnable() {
public void run() {
TextView tv = (TextView) findViewById(R.id.textView1);
tv.setText(SessionID);
}
});
} catch (Exception e) {
e.printStackTrace();
}
}
};
loginThread.start();
}
这里是我要调用的wsdl文件的一部分：
<wsdl:definitions name="DWService" targetNamespace="http://tempuri.org/">
<wsdl:types>
<xsd:schema elementFormDefault="qualified" targetNamespace="http://tempuri.org/">
<xsd:element name="Login">
<xsd:complexType>
<xsd:sequence>
<xsd:element minOccurs="0" name="userName" nillable="true" type="xsd:string"/>
<xsd:element minOccurs="0" name="password" nillable="true" type="xsd:string"/>
<xsd:element minOccurs="0" name="organization" nillable="true" type="xsd:string"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
我对Ksoap和网络服务并没有太多的了解，所以我希望有人可以帮我解决这个问题：）
问候。
修改
我尝试使用？svc代替 - ＆gt;相同的错误：（
修改
这里的WSDL文件的标头可能是我的命名空间是假的
<?xml version="1.0" encoding="UTF-8"?>
-<wsdl:definitions xmlns:wsam="http://www.w3.org/2007/05/addressing/metadata" xmlns:wsx="http://schemas.xmlsoap.org/ws/2004/09/mex"
xmlns:wsa10="http://www.w3.org/2005/08/addressing"
xmlns:msc="http://schemas.microsoft.com/ws/2005/12/wsdl/contract" xmlns:wsaw="http://www.w3.org/2006/05/addressing/wsdl" xmlns:wsap="http://schemas.xmlsoap.org/ws/2004/08/addressing/policy" xmlns:wsp="http://schemas.xmlsoap.org/ws/2004/09/policy" xmlns:wsa="http://schemas.xmlsoap.org/ws/2004/08/addressing" xmlns:tns="http://tempuri.org/"
xmlns:soap12="http://schemas.xmlsoap.org/wsdl/soap12/"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd"
xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/"
xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/"
targetNamespace="http://tempuri.org/" name="DWService">
-<wsdl:types>-
<xsd:schema targetNamespace="http://tempuri.org/" elementFormDefault="qualified">-
<xsd:element name="Login">-
<xsd:complexType>-
<xsd:sequence>
<xsd:element name="userName" type="xsd:string" nillable="true" minOccurs="0"/>
<xsd:element name="password" type="xsd:string" nillable="true" minOccurs="0"/>
<xsd:element name="organization" type="xsd:string" nillable="true" minOccurs="0"/></xsd:sequence>
</xsd:complexType>
</xsd:element>
-<xsd:element name="LoginResponse">
-<xsd:complexType>-
<xsd:sequence>
<xsd:element name="LoginResult" type="q1:ClientServiceSession" nillable="true" minOccurs="0"
xmlns:q1="http://schemas.datacontract.org/2004/07/DocuWare.WebServices.GAPIFunctionality.DataContracts"/>
</xsd:sequence></xsd:complexType></xsd:element>
肥皂部分：
-<wsdl:binding name="BasicHttpBinding_IDWService" type="tns:IDWService">
<soap:binding transport="http://schemas.xmlsoap.org/soap/http"/>
-<wsdl:operation name="Login"><soap:operation style="document" soapAction="http://tempuri.org/IDWService/Login"/>
-<wsdl:input><soap:body use="literal"/></wsdl:input>
-<wsdl:output><soap:body use="literal"/></wsdl:output></wsdl:operation>
-<wsdl:operation name="Logoff"><soap:operation style="document" soapAction="http://tempuri.org/IDWService/Logoff"/>
-<wsdl:input><soap:body use="literal"/></wsdl:input>
-<wsdl:output><soap:body use="literal"/></wsdl:output></wsdl:operation>
-<wsdl:service name="DWService">
-<wsdl:port name="BasicHttpBinding_IDWService" binding="tns:BasicHttpBinding_IDWService"><soap:address location="http://localhost:9007/DWService"/></wsdl:port></wsdl:service>
希望你能帮助我;）
答案 0 :(得分：2)
使用Fiddler跟踪流量。可能服务器/服务正在返回Content-Length: 0
这可能是任何事情，在我的情况下，它是从客户端应用程序发送的Content-type不匹配和服务器端的预期内容类型。由于该异常清楚地表明ByteArrayInputStream已收到来自服务的长度<= 0 的内容。
我希望这会让你进行更多调查。
干杯，
答案 1 :(得分：1)
你在这行之后检查过调试吗？
SoapObject response = (SoapObject) Envelope.getResponse();
如果您已通过webservice返回了属性？也许没有数据返回
使用
int arraySize = response.getPropertyCount();
检查长度以了解您是否正在接收数据
我认为可以生成argumentException，因为你正在尝试 访问该属性而不在此处检查：
final String SessionID = response.getProperty("SessionID").toString();
测试propertyCount并告诉我们。
编辑：
请测试一下：
将SoapEnvelope从VER12更改为VER11
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
将webService URL从wdsl更改为此类型（svc）：
String URL = "http://host:8080/HelloWCF/Service1.svc";
答案 2 :(得分：1)
像这样使用：
<强> basicHttpBinding的：
SoapObject Request = new SoapObject(NAMESPACE, METHOD_NAME);
Request.addProperty("userName", "demo");
Request.addProperty("password", "demo1234");
Request.addProperty("organization", "Peters Engineering");
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet=true;
envelope.setOutputSoapObject(Request);
HttpTransportSE ht = new HttpTransportSE(URL);
try {
ht.call(SOAP_ACTION, envelope);
final SoapPrimitive response = (SoapPrimitive)envelope.getResponse();
我对您的代码进行了一些更改。
<强> 1）
SoapSerializationEnvelope Envelope = new SoapSerializationEnvelope（ SoapEnvelope.VER12）;
改为
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope（SoapEnvelope.VER11）;
<强> 2） 我已从您的代码中删除了此部分。
ht.debug = true;
第3）
SoapObject response =（SoapObject）Envelope.getResponse（）;
改为
SoapPrimitive response =（SoapPrimitive）envelope.getResponse（）;
确保您在清单中添加了互联网权限
<uses-permission android:name="android.permission.INTERNET"/>
如果您没有通过使用此输出获得输出，问题可能是您的 wsdl
了解更多 Reference 希望这会对你有所帮助。
<强> PS。
<强> WsHttpBinding的：
Element e = new Element();
e.setName("To");
e.setNamespace("http://www.w3.org/2005/08/addressing");
e.addChild(Node.TEXT,
"your URL HERE");
Element e1 = new Element();
e1.setName("Action");
e1.setNamespace("http://www.w3.org/2005/08/addressing");
e1.addChild(Node.TEXT,
"http://tempuri.org/IService1/HelloTest");
request.addProperty("Celsius", "32");
// use VER12 instead of VER11
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER12);
envelope.dotNet=true;
// add HederOut to envelope
envelope.headerOut = new Element[] { e, e1 };
envelope.setOutputSoapObject(request);
答案 3 :(得分：-3)
我的选择： 1.使用最新的3.1.0 ksoap2 jar：http://code.google.com/p/ksoap2-android/wiki/HowToUse?tm=2 2.将v12改为v11