Windows 7 64 SP1 MongoDB 2.2.0
鉴于此数据:
db.address_book.drop()
db.address_book.save({"_id":1, "addresses": [ {"zip": 10018} , {"zip": 10012} ] } )
db.address_book.save({"_id":2, "addresses": [ {"zip": 11216} , {"zip": 10012} ] } )
db.address_book.save({"_id":3, "addresses": [ {"zip": 11215} , {"zip": 10010} ] } )
db.address_book.save({"_id":4, "addresses": [ {"zip": 10011} , {"zip": 10041} ] } )
db.address_book.save({"_id":5, "addresses": [ {"zip": 97202} , {"zip": 97201} ] } )
db.address_book.save({"_id":6, "addresses": [ {"zip": 10038} , {"zip": 97201} ] } )
我想要所有文件,其中任何邮政编码都在10012-10040范围内。换句话说,我想:
{ "_id" : 1, "addresses" : [ { "zip" : 10018 }, { "zip" : 10012 } ] }
{ "_id" : 2, "addresses" : [ { "zip" : 11216 }, { "zip" : 10012 } ] }
{ "_id" : 6, "addresses" : [ { "zip" : 10038 }, { "zip" : 97201 } ] }
此查询返回所需的结果:
db.address_book.find( { "addresses": { $elemMatch: { "$and" :[ { "zip": {$gte: 10012} } , {"zip": {$lte: 10040} } ] } } } )
问题:这是获得结果的最短(最优雅)查询吗?
每个查询:
db.address_book.find( { "addresses": { $elemMatch: { "zip": {$gte: 10012} , "zip": {$lte: 10040} } } } )
db.address_book.find( {"addresses.zip" : {$gte:10012, $lte:10040} } )
db.address_book.find( {"$and" :[ { "addresses.zip": {$gte: 10012} } , {"addresses.zip": {$lte: 10040} } ] } )
返回:
{ "_id" : 1, "addresses" : [ { "zip" : 10018 }, { "zip" : 10012 } ] }
{ "_id" : 2, "addresses" : [ { "zip" : 11216 }, { "zip" : 10012 } ] }
{ "_id" : 3, "addresses" : [ { "zip" : 11215 }, { "zip" : 10010 } ] }
{ "_id" : 4, "addresses" : [ { "zip" : 10011 }, { "zip" : 10041 } ] }
{ "_id" : 6, "addresses" : [ { "zip" : 10038 }, { "zip" : 97201 } ] }
如果第一种方法最短,则会产生复杂的C ++查询:
mongo::Query selector = QUERY("addresses" << BSON("$elemMatch" <<
BSON("$and" <<BSON_ARRAY(BSON("zip" << BSON("$gte"<<10012)) <<
BSON("zip" << BSON("$lte" << 10040))))));
我认为这是一个常见的查询我错了吗?
答案 0 :(得分:2)
我认为这个案例中最干净,最优雅的查询是你列出的几个人的组合:
db.address_book.find({addresses: {$elemMatch: {zip: {$gte:10012, $lte:10040}}}})