Question

我很难弄清楚我的PHP表单在process.php上处理的原因，但没有返回带有相应$ message的表单页面。我错过了一行代码吗？我自己写了这个，这是第一次。

这是我的HTML：

<!DOCTYPE html>
<html lang="en">
<head>
<title>Test Contact Form - jQuery</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script src="http://malsup.github.com/jquery.form.js"></script>
<script type="text/javascript" src="js/main.js"></script>

</head>
<body>    
    <h3>Contact Us</h3>
    <?php echo $contact_message; ?>
    <form id="myForm" method="post" action="process.php">
        <input name="name" type="text" value="<?php echo $_POST[name]; ?>" placeholder="Name" required/>
        <br>
        <input name="email" type="email" value="<?php echo $_POST[email]; ?>" placeholder="you@yourmail.com" required/>
        <br>
        <textarea name="message" class="message" placeholder="We can answer your questions." required>
            <?php echo $_POST[message]; ?>
        </textarea>
        <br>
        <button type="submit" name="submit" class="btn send">
            <img src="img/send.png">
        </button>
        <br>
        <?php echo $contact_success_message; ?>
    </form>
    <!--close contact form-->    
</body>
</html>

这是我的process.php

<?php

//checks for valid email
function is_valid_email($email) {
    $result = true;
    $pattern = '/^([a-z0-9])(([-a-z0-9._])*([a-z0-9]))*\@([a-z0-9])(([a-z0-9-])*([a-z0-9]))+(\.([a-z0-9])([-a-z0-9_-])?([a-z0-9])+)+$/i';
    if(!preg_match($pattern, $email)) {
        $result = false;
    }
    return $result;
}

//when send is pressed, validate fields
if(isset($_POST['submit'])) {
    $valid = true;
    $contact_message = '';
    if ( $_POST['name'] == "" ) {
        $contact_message .= "You forgot to tell us your name. ";
        $valid = false; 
    }
    if ( !is_valid_email($_POST['email']) ) {
        $contact_message .= "A valid email is required, don't worry we don't share it with anyone. "; 
        $valid = false; 
    }
    if ( $_POST['message'] == "" ) {
        $contact_message .= "What did you want to ask us? ";
        $valid = false; 
    }
    //if everything checks out, send the message! 
    if ( $valid == true ) {
        $safe_email = str_replace("\r\n","",$_POST[email]);
        $mail = "From: $_POST[name]\n";
        $mail .= "Email: $_POST[email]\n";
        $mail .= "$_POST[message]\n";
        mail('ME@MYEMAIL.COM','New Contact from RN+',$mail,"From: $safe_email\r\n");
        $contact_success_message = 'Brilliant I say! We will be in contact with you shortly.';
        //clear form when submission is successful
        unset($_POST);
    }
}
?>

我可以发誓说我以前用过这个，但这次它没有回到联系页面。

Answer 1

看起来你打算使用这样的代码：

form.php的

<?php include 'process.php'; ?>
<!DOCTYPE html>
<html lang="en">
<head>
<title>Test Contact Form - jQuery</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script src="http://malsup.github.com/jquery.form.js"></script>
<script type="text/javascript" src="js/main.js"></script>

</head>
<body>

<h3>Contact Us</h3>
            <?php echo $contact_message; ?>
            <form id="myForm" method="post" action="process.php">
                <input name="name" type="text" value="<?php echo $_POST[name]; ?>" placeholder="Name" required/><br>
                <input name="email" type="email" value="<?php echo $_POST[email]; ?>" placeholder="you@yourmail.com" required/><br>
                <textarea name="message" class="message" placeholder="We can answer your questions." required><?php echo $_POST[message]; ?></textarea><br>
                <button type="submit" name="submit" class="btn send"><img src="img/se
__
formnd.png"></button><br>
                <?php echo $contact_success_message; ?>
            </form><!--close contact form-->

</body>
</html>

表单处理器将设置您在HTML代码中输出的相应变量。由于process.php检查方法是否为POST，因此您不必在表单页面中执行此操作。

Answer 2

如果您希望process.php重定向回您的表单，您需要添加一个PHP标头代码，如：header('Location: http://www.example.com/form.php');

如果要将任何数据传回原始页面，请将其作为GET变量包含在URL中：header('Location: http://www.example.com/form.php?message='.$messagetext);然后，您可以使用GET在表单页面上检索此内容：{{1} }

重定向后不要忘记echo $contact_success_message = $_GET['message'];！

Answer 3

如果您没有任何理由排除单个PHP页面，可以将两个（表单和进程）合并到一个php页面中。

<?php
//checks for valid email function
...
if(isset($_POST['submit'])) {
...
}
?>
...your HTML goes here...

如果没有提交数据，这将只显示表单，如果表单已提交，将“重新加载”页面，执行操作并显示相应的消息。将表单操作更改为action=""，以便文件发布到自身。

Answer 4

我建议使用jQuery验证。它更容易，并且可以帮助您回复消息时遇到的任何问题。

http://docs.jquery.com/Plugins/Validation

像这样......

$("#myForm").validate({
rules: {
    name: { required: true; }
},
messages: {
name: "You forgot to tell us your name.",
}

}）;

您可以为电子邮件字段和整个表单执行此操作。你可以在网上找到很多例子。

只需包含您的其他字段即可。如果您这样做，验证是客户端，表格将处理，然后您转发到感谢您联系我们页面。

PHP表单不在process.php中处理

4 个答案: