Sharepoint将项目添加到图片库

时间:2009-08-27 12:04:59

标签: c# sharepoint file-io wss

我想使用c#将项目添加到图片库中。这就是我将字段添加到普通项目的方式:

var item = list.Items.Add();
item["Title"] = "Item title";
item.Update();

我该如何添加图片?图片存储在文件系统中,即c:\ myfile.png我iamgine我需要使用SPFile但不确定如何。

2 个答案:

答案 0 :(得分:3)

这是从文件

创建byte []的方法
private byte [] StreamFile(string filename)
{
  FileStream fs = new FileStream(filename, FileMode.Open,FileAccess.Read);
  // Create a byte array of file stream length
  byte[] ImageData = new byte[fs.Length];
  //Read  block of bytes from stream into the byte array
  fs.Read(ImageData,0,System.Convert.ToInt32(fs.Length));
  //Close the File Stream
  fs.Close();
  return ImageData;
}

// then use the following to add the file to the list
list.RootFolder.Files.Add(fileName, StreamFile(fileName));

答案 1 :(得分:1)

就像向文档库添加文件一样简单。以下是可帮助您完成此操作的代码段。我已经从这个link获取代码,因为格式化不合适我在这里粘贴了一个干净的版本

try
        {
            byte[] imageData = null;
            if (flUpload != null)
            {
                // This condition checks whether the user has uploaded a file or not
                if ((flUpload.PostedFile != null) && (flUpload.PostedFile.ContentLength > 0))
                {
                    Stream MyStream = flUpload.PostedFile.InputStream;
                    long iLength = MyStream.Length;
                    imageData = new byte[(int)MyStream.Length];
                    MyStream.Read(imageData, 0, (int)MyStream.Length);
                    MyStream.Close();
                    string filename = System.IO.Path.GetFileName(flUpload.PostedFile.FileName);                                                
                   SPPictureLibrary pic = (SPPictureLibrary)SPContext.Current.Web.Lists["Images"];//Images is the picture library name
                   SPFileCollection filecol = ((SPPictureLibrary)SPContext.Current.Web.Lists["Images"]).RootFolder.Files;//getting all the files which is in pictire library
                   filecol.Add(filename, imageData);//uploading the files to picturte library

                }
            }                
        }
        catch (Exception ex)
        {
            //handle it
        }