我在将下面的SQL转换为Zend Db查询时遇到了一些问题。
$select = ' SELECT s.id, i.id as instance_id, i.reference, i.name, i.sic_code, i.start_date
FROM sles s
JOIN sle_instances i
ON s.id = i.sle_id
WHERE i.id = ( SELECT MAX(id)
FROM sle_instances
WHERE sle_id = s.id
)
ORDER BY i.name ASC';
我之前已经得到了代码 - 但Zend Db没有正确生成查询。谁能告诉我我错过了什么?
$select = $db->select() ->from('sles', array( 'id',
'instance_id' => 'sle_instances.id',
'reference' => 'sle_instances.reference',
'name' => 'sle_instances.name',
'sic_code' => 'sle_instances.sic_code',
'start_date' => 'sle_instances.start_date'
)
)
->join('sle_instances', 'sles.id = sle_instances.sle_id')
->where('sles.id = (SELECT MAX(id) FROM sle_instances WHERE sle_id = sles.id)')
->order('sle_instances.name ASC');
SQL确实有用。我正在使用Zend Db重写它,因为我希望使用Zend Paginator功能。
非常感谢任何帮助。
PJ
答案 0 :(得分:32)
如果你愿意,你可以采取@ karim79所做的事情,并将你的子选择转换为$ this-> select()以及......
$subselect = $db->select()
->from('sle_instances', array(new Zend_Db_Expr('max(id)')))
->where('sle_id = s.id');
$select = $db->select()->from(array("s" => "sles"),
array("s.id","i.id as instanceid","i.reference","i.name","i.sic_code","i.start_date"))
->join(array('i' => "sle_instances"),"s.id = i.sle_id",array())
->where("i.id = ($subselect)")
->order('i.name asc');
print($select);
//SELECT `s`.`id`, `i`.`id` AS `instanceid`, `i`.`reference`, `i`.`name`, `i`.`sic_code`, `i`.`start_date` FROM `sles` AS `s` INNER JOIN `sle_instances` AS `i` ON s.id = i.sle_id WHERE (i.id = (SELECT max(id) FROM `sle_instances` WHERE (sle_id = s.id))) ORDER BY `i`.`name` asc
答案 1 :(得分:20)
此:
$select = $db->select()->from(array("s" => "sles"), array("s.id","i.id as instanceid","i.reference","i.name","i.sic_code","i.start_date"))
->join(array('i' => "sle_instances"),"s.id = i.sle_id",array())
->where("i.id = (select max(id) from sle_instances where sle_id = s.id)")
->order('i.name asc');
给出这个:
"SELECT `s`.`id`, `i`.`id` AS `instanceid`, `i`.`reference`, `i`.`name`, `i`.`sic_code`, `i`.`start_date` FROM `sles` AS `s`
INNER JOIN `sle_instances` AS `i` ON s.id = i.sle_id WHERE (i.id = (select max(id) from sle_instances where sle_id = s.id)) ORDER BY `i`.`name` asc"
答案 2 :(得分:3)
我有一个非常类似的问题,我发现这个查询可以很容易地编写如下:
$select = $db->select()
->from (
array("s" => "sles"),
array(
"s.id",
"instanceid" => "i.id",
"i.reference",
"i.name",
"i.sic_code",
"i.start_date")
)
->join(
array('i' => "sle_instances"),
"s.id = i.sle_id",
array()
)
->where ("i.id = (" .
$db->select()
->from('sle_instances', array(new Zend_Db_Expr('max(id)')))
->where('sle_id = s.id');
.")")
->order('i.name asc');
print($select);
这与人们在这里已经说过的完全相同。但我觉得它更容易阅读,因为子查询依赖性更明显。
答案 3 :(得分:1)
好问题!谢谢你这个。如果您在订单后尝试创建一个组,也可以使用这种语法与以下内容非常相似
$subquery = $this->_datawarehouse->select()
->from('revenueLog')
->where('Date '.$ReturnDate)
->order('Date DESC');
$this->view->end = microtime();
$format = new Zend_Db_Expr('DATE_FORMAT(`Date`,"%d-%m-%y")');
$select = $this->_datawarehouse->select()
->from(array('subquery'=>$subquery))
->group('Client')
->group($format)
->order('Vertical ASC')
->order('Revenue DESC');
echo $select->__ToString();
$stmt = $this->_datawarehouse->query($select);
$data = $stmt->fetchAll();
任何想知道$ ReturnDate的人都是基于用户输入的字符串,通常最终是“BETWEEN'date1'和'date2'”