Question

如何将整数数组传入构造函数？

这是我的代码：

import java.io.*;
import java.util.*;

public class Temperature implements Serializable
{
    private int[] temps = new int [7];
    public Temperature(int[] a)
    {
        for(int i=0; i < 7; i++)
        {
            temps[i] = a[i];
        }

    }
    public static void main(String[] args)
    {
        Temperature i = new Temperature(1,2,3,4,5,6,7);
    }
}

给出的错误是：

Temperature.java:17: error: constructor Temperature in class Temperature cannot be applied to given types;
        Temperature i = new Temperature(1,2,3,4,5,6,7);
                        ^
  required: int[]
  found: int,int,int,int,int,int,int
  reason: actual and formal argument lists differ in length
1 error

Answer 1

对于当前调用，您需要var-args constructor 代替。因此，您可以更改constructor声明以获取 var-arg参数： -
```
public Temperature(int... a) {
     /**** Rest of the code remains the same ****/
}
```
或者，如果您想使用an array作为参数，那么您需要pass an array这样的构造函数 -
```
Temperature i = new Temperature(new int[] {1,2,3,4,5,6,7}); 
```

Answer 2

这应该这样做： new Temperature（new int [] {1,2,3,4,5,6,7}）

Answer 3

您可以通过以下方式执行此操作

import java.io.*;
import java.util.*;

public class Temperature implements Serializable
{
    private int[] temps = new int [7];
    public Temperature(int[] a)
    {
        for(int i=0; i < 7; i++)
        {
            temps[i] = a[i];
        }

    }
    public static void main(String[] args)
    {
        int [] vals = new int[]{1,2,3,4,5,6,7};  
        Temperature i = new Temperature(vals);
    }




}

Answer 4

 public static void main(String[] args)
    {
    Temperature i = new Temperature(new int[] {1,2,3,4,5,6,7});
    }

创建一个接受整数数组的构造函数

4 个答案: