我的ajax成功函数在将数据发送到我的数据库后没有执行脚本,数据在我的数据库上保存得很好,但之后一切都停止了。什么可能是错的?
$(document).ready(function() {
$(".wall_update").click(function() {
var element = $(this);
var boxval = $("#content").val();
var dataString = 'content=' + boxval;
$("#form1").validationEngine({
type: "POST",
ajaxSubmit: true,
ajaxSubmitFile: "update_ajax.php",
cache: false,
success: function(html) {
alert('success');
$("ol#update").prepend(html);
$("ol#update li:first").slideDown("slow");
document.getElementById('content').value = '';
$('#content').value = '';
$('#content').focus();
$("#flash").hide();
}
});
});
});
<?php
include("db.php");
include("tolink.php");
if(isSet($_POST['content']))
{
$id=time();//Demo Use
$msg=$_POST['content'];
$date=date("M j, Y ");
$sql=mysql_query("insert into appointments(message,date_sent)values('$msg','$date')");
$result=mysql_query("select * from appointments order by msg_id desc");
$row=mysql_fetch_array($result);
$id=$row['msg_id'];
$msg=$row['message'];
$date=$row['date_sent'];
$msg= nl2br($msg);
$msg="<br>{$msg}<br>{$date}";
}
?>
<li class="bar<?php echo $id; ?>">
<div align="left" class="post_box">
<span style="padding:10px"><?php echo $msg; ?> </span>
<span class="delete_button"><a href="#" id="<?php echo $id; ?>" class="delete_update">X</a></span>
<span class='feed_link'><a href="#" class="comment" id="<?php echo $id; ?>">comment</a></span>
</div>
<div id='expand_box'>
<div id='expand_url'></div>
</div>
<div id="fullbox" class="fullbox<?php echo $id; ?>">
<div id="commentload<?php echo $id; ?>" >
</div>
<div class="comment_box" id="c<?php echo $id; ?>">
<form method="post" action="" name="<?php echo $id; ?>">
<textarea class="text_area" name="comment_value" id="textarea<?php echo $id; ?>">
</textarea><br />
<input type="submit" value=" Comment " class="comment_submit" id="<?php echo $id; ?>"/>
</form>
</div>
</div>
</li>
<div align="left">
<form method="post" name="form" action="" id="form1">
<table cellpadding="0" cellspacing="0" width="500px">
<tr><td align="left"><div align="left"><h3>What are you doing?</h3></div></td></tr>
<tr>
<td style="padding:4px; padding-left:10px;" class="update_box">
<textarea class="validate[custom[last]] text-input" cols="30" rows="10" style="width:480px;font-size:14px; font-weight:bold" name="content" id="content" ></textarea><br />
<input type="submit" value="Update" name="submit" class="wall_update"/>
</td>
</tr>
</table>
</form>
</div>
<ol id="update" class="timeline">
// Display here after sending data to the database
</ol>
答案 0 :(得分:2)
$('#content').value = '';
jQuery没有value
属性,您应该使用val
:
$('#content').val('');
value
是DOM Input对象的属性。