Question

有没有办法（希望是干净的）我可以在这里做同样的事情而不分配状态值？当if条件在同一行时，我遇到if条件返回布尔值（而不是函数）的问题。

onItemChanged = (event,ui) ->
  input_element = event.target
  list_id = input_element.getAttribute('list_id')
  state = if input_element.checked
            onItemChecked //function of int -> nothing
          else
            onItemUnchecked //function of int -> nothing

  state (list_id )

Answer 1

像这样：

onItemChanged = (event, ui) ->
  input = event.target
  state = if input.checked then onItemChecked else onItemUnchecked
  state input.getAttribute('list_id')

甚至：

onItemChanged = ({target: input}, ui) ->
  state = if input.checked then onItemChecked else onItemUnchecked
  state input.getAttribute('list_id')

Answer 2

不确定您是否认为它更干净，但您也可以直接调用if表达式的结果：

onItemChanged = (event,ui) ->
  input_element = event.target
  list_id = input_element.getAttribute('list_id')
  (if input_element.checked then onItemChecked else onItemUnchecked) list_id

或者只是拨打onItemChecked内的onItemUnchecked或if：

onItemChanged = (event,ui) ->
  input_element = event.target
  list_id = input_element.getAttribute('list_id')
  if input_element.checked 
    onItemChecked list_id
  else 
    onItemUnchecked list_id

将条件和函数调用放在一行中

2 个答案: