Question

我有一张这样的表：

id | name 
----------------
 1 | àbbot
 2 | about
 3 | zorro

我想在不区分大小写的上下文中选择第一个字母，如下所示：

let
----------
a
z

但是，任何具有任何unicode整理的内容都会产生相同的错误结果：

SELECT LOWER(SUBSTR(name,1,1)) AS let FROM t GROUP BY let

SELECT LOWER(SUBSTR(name,1,1)) AS let FROM t GROUP BY letter ORDER BY let ASC

SELECT * FROM
     (SELECT LOWER(SUBSTR(name,1,1)) AS let FROM t ORDER BY let DESC) AS x
GROUP BY let ORDER BY let ASC

错误的结果：

let
----------
à
z

有没有一种方法可以修复排序，而无需投射？（因为我也必须覆盖非拉丁语言，例如日语）。

也许我有一个旧版本的MySQL ...你能在你的环境中测试查询吗？

提前谢谢！

Answer 1

没关系，找到了解决方案

SELECT UPPER(SUBSTR(name,1,1)) AS let FROM 
    (SELECT name FROM t ORDER BY name DESC) AS x
GROUP BY let ORDER BY let ASC

如何在不区分大小写的上下文中选择第一个字母？

1 个答案: