我正试图通过Class clazz实例化一个新对象:
代码:
public class EntityType {
private Map json = null;
public EntityType(Map json){
this.json = json;
}
public <T> T getAs(Class<T> clazz){
final Class<T> clz = clazz;
T obj = null;
try {
if (checkMap(json)){
obj = clz.newInstance();
}
} catch (Exception e){
if (e instanceof InstantiationException){
e.printStackTrace();
} else if (e instanceof IllegalAccessException){
e.printStackTrace();
} else {
e.printStackTrace();
}
}
return obj;
}
}
这就是我使用代码的方式:
EntityType type = new EntityType(map); // map contains values
User user = type.getAs(User.class);
上述代码抛出 java.lang.InstantiationException
。
我的代码可能有什么问题?
更新
@Entity(name = "user")
public class User {
@Id
private String id;
@Column
private String name;
@Column
private Long age;
public User() {}
// Setters and getter
}
完整堆栈跟踪:
java.lang.InstantiationException: org.goo.AnnotationTest$User
at java.lang.Class.newInstance0(Class.java:357)
at java.lang.Class.newInstance(Class.java:325)
at org.goodb.client.Goo$EntityType.getAs(Goo.java:90)
at org.goo.AnnotationTest.doTest(AnnotationTest.java:97)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:601)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
at org.springframework.test.context.junit4.statements.RunBeforeTestMethodCallbacks.evaluate(RunBeforeTestMethodCallbacks.java:74)
at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
at org.springframework.test.context.junit4.statements.RunAfterTestMethodCallbacks.evaluate(RunAfterTestMethodCallbacks.java:83)
at org.springframework.test.context.junit4.statements.SpringRepeat.evaluate(SpringRepeat.java:72)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:231)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:50)
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193)
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42)
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184)
at org.springframework.test.context.junit4.statements.RunBeforeTestClassCallbacks.evaluate(RunBeforeTestClassCallbacks.java:61)
at org.springframework.test.context.junit4.statements.RunAfterTestClassCallbacks.evaluate(RunAfterTestClassCallbacks.java:71)
at org.junit.runners.ParentRunner.run(ParentRunner.java:236)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner.java:174)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)
答案 0 :(得分:1)
您的用户类中可能没有默认构造函数
答案 1 :(得分:1)
异常堆栈跟踪说
java.lang.InstantiationException: org.goo.AnnotationTest$User
表明User
是嵌套或内部类而不是顶级类。静态嵌套类的行为类似于顶级类,但对于非静态内部类,每个实例都与其包含类的特定实例相关联,并且编译器在参数列表的前面添加一个额外参数,以便每个构造函数都传入适当的包含实例。源代码中的内容是什么
public User() {}
实际上在字节码中对应于
public User(AnnotationTest containingInstance) { this.container = containingInstance; }
(不是那些参数/字段名称,但你明白了)。所以你的User
类实际上没有无参构造函数。
如果您将User
类声明为顶级类或将其标记为static
,那么它将按预期工作。
答案 2 :(得分:0)
您有一个通用方法,但您没有传递类型参数。试试这个:
User user = type.<User>getAs(User.class);
如果您与我们分享更多代码,我可以为您提供更多帮助。例如,我想看到完整的堆栈跟踪和User
类。
答案 3 :(得分:0)
根据javadoc描述:
* @exception InstantiationException
* if this {@code Class} represents an abstract class,
* an interface, an array class, a primitive type, or void;
* or if the class has no nullary constructor;
* or if the instantiation fails for some other reason.
我认为你没有“nullary constructor”,或者很可能说:默认构造函数。