使用CI和电子邮件类完成php表单后,我能够收到包含用户数据的HTML电子邮件 - 很棒。现在,除了CI验证,我想包括客户端验证(AJAX)与一个很好的fadeIn或fadeOut效果,并仍然运行CI验证,以防javascript关闭。
此处包含的代码是我迄今为止从各种来源获得的代码,我知道这不完整但不确定我是否在正确的轨道上?到目前为止,我所拥有的表单仍然可以正常工作,我认为它仍在运行CI验证脚本,并且没有发生任何影响。
如果有人可以指导我到目前为止我遇到错误的地方,如果有可能,接下来要采取什么步骤,我会感到很恐慌?以下是支持我的问题的代码:
查看
<div id="contact">
<?php
//This is loaded in the view as it wont be used in the other pages
$this->load->helper('form');
echo form_open('contact/send_email');
//success message if passed validation checks
echo $success;
// empty div for error messages (php)
if(validation_errors() != ""){
echo '<h3>Please correct the following errors:</h3>';
echo '<div id="errors">';
echo validation_errors();
echo '</div>';
}
echo form_label('Name: ', 'name');
$data = array (
'name' => 'name',
'id' => 'name',
'value' => set_value('name')
);
echo form_input($data);
echo form_label('Email: ', 'email');
$data = array (
'name' => 'email',
'id' => 'email',
'value' =>set_value('email')
);
echo form_input($data);
echo form_label('Message: ', 'message');
$data = array (
'name' => 'message',
'id' => 'message',
'value' =>set_value('message')
);
echo form_textarea($data);
?>
<br />
<?php
echo form_submit('submit', 'Send');
echo form_close();
?>
----------- AJAX -------------------
$(function() {
$('form').click(function() {
// get the form values
var form_data = {
name: $('name').val(),
email: $('email').val(),
message: $('message').val()
};
// send the form data to the controller
$.ajax({
url: "<?php echo site_url('contact/send_email'); ?>",
type: "post",
data: form_data,
success: function(msg)
{
if(msg.validate)
{
$('form').prepend('<p>Message sent!</p>');
$('p').delay(3000).fadeOut(500);
}
else
$('form').prepend('<div id="errors">Message Error</div>');
$('p').delay(3000).fadeOut(500);
}
});
// prevents from refreshing the page
return false;
});
});
</script>
CONTROLLER
类联系人扩展CI_Controller {
function __construct() {
parent::__construct();
}
public function index()
{
$data['success'] = '';
$data['page_title'] = 'Contact';
$data['content'] = 'contact';
$this->load->view('template', $data);
}
public function send_email (){
$this->load->library('form_validation');
[SET RULES ARE LOCATED HERE]
[ERROR DELIMITERS HERE]
if ($this->form_validation->run() === FALSE) {
$data['success'] = '';
$data['page_title'] = 'Contact';
$data['content'] = 'contact';
$this->load->view('template', $data);
}else{
$data['success'] = 'The email has successfully been sent';
$data['name'] = $this->input->post('name');
$data['email'] = $this->input->post('email');
$data['message'] = $this->input->post('message');
$html_email = $this->load->view('html_email', $data, true);
//load the email class
$this->load->library('email');
$this->email->from(set_value('email'), set_value('name'));
$this->email->to('-----EMAIL----');
$this->email->subject('Message from Website');
$this->email->message($html_email);
$this->email->send();
$data['page_title'] = 'Contact';
$data['content'] = 'contact';
$this->load->view('template', $data);
return null;
}
}
}
答案 0 :(得分:1)
让我试着在这个社区发表我的第一个答案:
1.这是jQuery文件,因此您应该使用.submit()方法来处理表单提交
$('form').submit(function() {
但是如果你想使用click,你应该用'submit'按钮
绑定它 $('input[type="submit"]').click(function() {
2。您可以使用.serialize()方法
,而不是将所有数据都收集到数组中 data: $('form').serialize(),
3。在您的控制器中,为什么要加载视图?它是Ajax调用,所以常见的方法是返回JSON响应取决于你的结果:
if ($this->form_validation->run() === TRUE) {
$data['success'] = 'The email has successfully been sent';
$data['name'] = $this->input->post('name');
$data['email'] = $this->input->post('email');
$data['message'] = $this->input->post('message');
$html_email = $this->load->view('html_email', $data, true);
//load the email class
$this->load->library('email');
$this->email->from(set_value('email'), set_value('name'));
$this->email->to('-----EMAIL----');
$this->email->subject('Message from Website');
$this->email->message($html_email);
$this->email->send();
$response->validate = true;
echo json_encode($response);
}
在这种情况下,我消除了FALSE,因为你已经在回调函数上检查了结果:
success: function(msg)
{
if(msg.validate)
{
$('form').prepend('<p>Message sent!</p>');
$('p').delay(3000).fadeOut(500);
}
else
$('form').prepend('<div id="errors">Message Error</div>');
$('p').delay(3000).fadeOut(500);
}
});
虽然这是2012年的问题,但希望能帮助那些偶然发现这个问题的人。