Question

我有一个JSON对象，其中包含以下内容：

[
  {
    "_id":"5078c3a803ff4197dc81fbfb",
    "email":"user1@gmail.com",
    "image":"some_image_url",
    "name":"Name 1"
  },
  {
    "_id":"5078c3a803ff4197dc81fbfc",
    "email":"user2@gmail.com",
    "image":"some_image_url",
    "name":"Name 2"
  }
]

我想将“_id”键更改为“id”，以便它变为

[
  {
    "id":"5078c3a803ff4197dc81fbfb",
    "email":"user1@gmail.com",
    "image":"some_image_url",
    "name":"Name 1"
  },
  {
    "id":"5078c3a803ff4197dc81fbfc",
    "email":"user2@gmail.com",
    "image":"some_image_url",
    "name":"Name 2"
  }
]

我如何使用Javascript，jQuery或Ruby，Rails？

感谢。

Answer 1

var json = '[{"_id":"5078c3a803ff4197dc81fbfb","email":"user1@gmail.com","image":"some_image_url","name":"Name 1"},{"_id":"5078c3a803ff4197dc81fbfc","email":"user2@gmail.com","image":"some_image_url","name":"Name 2"}]';

var obj = JSON.parse(json)[0];
obj.id = obj._id;
delete obj._id;

json = JSON.stringify([obj]);

这会将json更改为：

[{"email":"user1@gmail.com","image":"some_image_url","name":"Name 1","id":"5078c3a803ff4197dc81fbfb"}]

由于订单在JSON中的名称/值对中没有意义，因此这与您想要的结果相同。

Answer 2

在这种情况下，最简单的方法是使用字符串替换。序列化JSON将无法正常工作，因为_id将成为对象的属性名称，更改属性名称不是一项简单的任务（至少在大多数语言中都没有，在javascript中也不是那么糟糕）。而只是做;

jsonString = jsonString.replace("\"_id\":", "\"id\":");

Answer 3

正如evanmcdonnal所提到的，最简单的解决方案是将其作为字符串而不是JSON处理，

＆＃13;

var json = [{"_id":"5078c3a803ff4197dc81fbfb","email":"user1@gmail.com","image":"some_image_url","name":"Name 1"},{"_id":"5078c3a803ff4197dc81fbfc","email":"user2@gmail.com","image":"some_image_url","name":"Name 2"}];
    
json = JSON.parse(JSON.stringify(json).split('"_id":').join('"id":'));

document.write(JSON.stringify(json));

＆＃13;

这会将给定的JSON数据转换为字符串并替换＆＃34; _id＆＃34;到＆＃34; id＆＃34;然后将其转换回所需的JSON格式。但我使用split和join代替replace，因为replace只会替换字符串的第一个匹配项。

Answer 4

如果要重命名某个键的所有出现次数，可以使用带g选项的正则表达式。例如：

var json = [{"_id":"1","email":"user1@gmail.com","image":"some_image_url","name":"Name 1"},{"_id":"2","email":"user2@gmail.com","image":"some_image_url","name":"Name 2"}];

str = JSON.stringify(json);

现在我们在str。

中使用字符串格式的json

使用带有 g 选项的正则表达式将所有出现的“_id”替换为“id”：

str = str.replace(/\"_id\":/g, "\"id\":");

并返回json格式：

json = JSON.parse(str);

现在我们的json带有想要的密钥名称。

Answer 5

如果您的对象看起来像这样：

obj = {
    "_id":"5078c3a803ff4197dc81fbfb",
    "email":"user1@gmail.com",
    "image":"some_image_url",
    "name":"Name 1"
   }

JavaScript中最简单的方法可能是：

obj.id = obj._id
del object['_id']

结果，你会得到：

obj = {
    "id":"5078c3a803ff4197dc81fbfb",
    "email":"user1@gmail.com",
    "image":"some_image_url",
    "name":"Name 1"
   }

Answer 6

如果有人需要动态执行此操作：

jsonObject

replace现在将具有新密钥。

重要提示：

如果您的密钥没有被if函数更改，它将直接将其从数组中取出。您可能要在其中放置一些{{1}}语句。

Answer 7

如果要替换 JSON 对象的键，请使用以下逻辑

const student= {
  "key": "b9ed-9c1a04247482",
  "name": "Devaraju",
  "DOB" : "01/02/2000",
  "score" : "A+"
}
let {key, ...new_student} = {...student}
new_student.id= key

console.log(new_student)

Answer 8

如果要动态执行此操作，例如，您有一个要作为JSON对象的键应用的数组：

你的数组将是：

var strs = ['http://example.com?param', 'http://example.com?param=123', 'http://example.com?param&another','http://example.com?params'];
var rx = /[?&]param(?![^&=])/;
for (var s of strs) {
  console.log(s, "=>", rx.test(s))
}

现在您有一个JSON数组，如：

var keys = ["id", "name","Address","Phone"] // The array size should be same as JSON Object keys size

您生成的JSON数组将如下：

var jArray = [
  {
    "_id": 1,
    "_name": "Asna",
    "Address": "NY",
    "Phone": 123
  },
  {
    "_id": 2,
    "_name": "Euphoria",
    "Address": "Monaco",
    "Phone": 124
  },
  {
    "_id": 3,
    "_name": "Ahmed",
    "Address": "Mumbai",
    "Phone": 125
  }
]

$.each(jArray ,function(pos,obj){
    var counter = 0;
    $.each(obj,function(key,value){
        jArray [pos][keys[counter]] = value;
        delete jArray [pos][key];
        counter++;
    })  
})

Answer 9

可以使用typeScript

function renameJson(json,oldkey,newkey) {    
 return Object.keys(json).reduce((s,item) => 
      item == oldkey ? ({...s,[newkey]:json[oldkey]}) : ({...s,[item]:json[item]}),{})   
}

示例：https://codepen.io/lelogualda/pen/BeNwWJ

Answer 10

通过使用地图功能，您可以做到这一点。请参考下面的代码。

var userDetails = [{
  "_id":"5078c3a803ff4197dc81fbfb",
  "email":"user1@gmail.com",
  "image":"some_image_url",
  "name":"Name 1"
},{
  "_id":"5078c3a803ff4197dc81fbfc",
  "email":"user2@gmail.com",
  "image":"some_image_url",
  "name":"Name 2"
}];

var formattedUserDetails = userDetails.map(({ _id:id, email, image, name }) => ({
  id,
  email,
  image,
  name
}));
console.log(formattedUserDetails);

Answer 11

尝试一下：

let jsonArr = [
    {
        "_id":"5078c3a803ff4197dc81fbfb",
        "email":"user1@gmail.com",
        "image":"some_image_url",
        "name":"Name 1"
    },
    {
        "_id":"5078c3a803ff4197dc81fbfc",
        "email":"user2@gmail.com",
        "image":"some_image_url",
        "name":"Name 2"
    }
]

let idModified = jsonArr.map(
    obj => {
        return {
            "id" : obj._id,
            "email":obj.email,
            "image":obj.image,
            "name":obj.name
        }
    }
);
console.log(idModified);

Answer 12

JSON.parse有两个参数。第二个参数reviver是一个转换函数，可以将其格式化为所需的输出格式。请参阅ECMA规范here。

在齐磊功能中：

如果我们返回undefined，则原始属性将被删除。
this是包含正在作为此函数处理的属性，属性名称为字符串，属性值作为此函数的参数的对象。

const json = '[{"_id":"5078c3a803ff4197dc81fbfb","email":"user1@gmail.com","image":"some_image_url","name":"Name 1"},{"_id":"5078c3a803ff4197dc81fbfc","email":"user2@gmail.com","image":"some_image_url","name":"Name 2"}]';

const obj = JSON.parse(json, function(k, v) {
    if (k === "_id") {
        this.id = v;
        return; # if return  undefined, orignal property will be removed
    }
    return v;
});

const res = JSON.stringify(obj);
console.log(res)

输出：

[{"email":"user1@gmail.com","image":"some_image_url","name":"Name 1","id":"5078c3a803ff4197dc81fbfb"},{"email":"user2@gmail.com","image":"some_image_url","name":"Name 2","id":"5078c3a803ff4197dc81fbfc"}]

如何重命名JSON密钥

12 个答案: