Question

我有以下代码。它运行，我得到我的结果，我认为退出重复有问题，在获得ipad名称后，脚本仍然保持运行直到超时。谁能告诉我代码有什么问题？谢谢！

set deviceName to "iPad"
tell application "System Events"
tell process "iTunes"
    activate
    repeat with i from 1 to the count of (row of outline 1 of scroll area 2 of window "iTunes")
        repeat with j from 1 to the count of static text of row i of outline 1 of scroll area 2 of window "iTunes"
            set xxxx to the value of item j of static text of row i of outline 1 of scroll area 2 of window "iTunes"
            if (xxxx contains deviceName) then
                print xxxx
                click row i of outline 1 of scroll area 2 of window "iTunes"
                exit repeat
            end if
            --exit repeat
        end repeat

    end repeat

end tell
end tell

Answer 1

如果要在找到第一个iPad后退出脚本，请将return repeat替换为return。

Answer 2

问题（你要求）是你重复一次。这意味着当你进入子循环并退出重复时，你将跳转到主循环。要从此处退出，您必须再次退出重复。

查看你的代码我不理解嵌套的重复循环。您可以删除包围/主重复，它将按预期工作。

set deviceName to "iPad"
tell application "System Events"
    tell process "iTunes"
        activate
        repeat with UIElement in rows of outline 1 of scroll area 2 of window "iTunes"
            if (value of static text of UIElement as text) begins with deviceName then return select UIElement
        end repeat
    end tell
end tell

我使用开头的原因是包含将点击之前的手柄菜单项。

退出重复后AppleScript不会停止运行

2 个答案: