我有两个片段Fragment1和Fragment2.当我启动应用程序时，两个片段中定义的函数都会被执行。因此启动需要很长时间（因为XML解析和列表视图的填充都在两个片段上执行）我需要减少应用程序的启动时间。它们是否可以在启动时执行Fragment1，并且Fragment2的执行带来了后台？这样用户就可以与Fragment1进行交互.Pragment2执行其功能而不会使用户不知情。
这是我的代码，
片段1 =＆GT;
public class Fragment1 extends Fragment{
public static String feedurl="http://www.abcd.com/en/rssfeeds/1_2_3_5/latest/rss.xml";
static String URL = "";
static final String KEY_HEAD = "item"; // parent node
static final String KEY_DATE = "pubDate";
public static String headflag="";
int f=0;
GridView list;
HeadlinesAdapter adapter;
private TextView mMessageView;
private Button mClearButton;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.first_fragment, container, false);
return v;
}
@Override
public void onViewCreated(View view, Bundle savedInstanceState) {
super.onViewCreated(view, savedInstanceState);
headlines.parse();
populate_listview();
}
public void populate_listview()
{
URL="http://www.abcd.com/en/rssfeeds/1_2_3_5/latest/rss.xml";
ArrayList<HashMap<String, String>> newsList = new ArrayList<HashMap<String, String>>();
XMLParser parser = new XMLParser();
String xml = parser.getXmlFromUrl(URL);
Document doc = parser.getDomElement(xml);
NodeList nl = doc.getElementsByTagName(KEY_HEAD);
NodeList itemLst = doc.getElementsByTagName("item");
String MarqueeStr="";
for (int i = 0; i < nl.getLength(); i++) {
HashMap<String, String> map = new HashMap<String, String>();
Element e = (Element) nl.item(i);
newsList.add(map);
}
list=(GridView)getActivity().findViewById(R.id.grid);
adapter=new Adapter1(getActivity(), newsList);
list.setAdapter(adapter);
}
Fragment2 =＆GT;
public class Fragment2 extends Fragment{
public static String feedurl="http://www.abcd.com/en/rssfeeds/1_2_3_5/latest/rss.xml";
static String URL = "";
static final String KEY_HEAD = "item"; // parent node
static final String KEY_DATE = "pubDate";
public static String headflag="";
int f=0;
GridView list;
HeadlinesAdapter adapter;
private TextView mMessageView;
private Button mClearButton;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.second_fragment, container, false);
return v;
}
@Override
public void onViewCreated(View view, Bundle savedInstanceState) {
super.onViewCreated(view, savedInstanceState);
sports.parse();
populate_listview();
}
public void populate_listview()
{
URL="http://www.abcd.com/en/rssfeeds/1_2_3_5/latest/rss.xml";
ArrayList<HashMap<String, String>> newsList = new ArrayList<HashMap<String, String>>();
XMLParser parser = new XMLParser();
String xml = parser.getXmlFromUrl(URL);
Document doc = parser.getDomElement(xml);
NodeList nl = doc.getElementsByTagName(KEY_HEAD);
NodeList itemLst = doc.getElementsByTagName("item");
String MarqueeStr="";
for (int i = 0; i < nl.getLength(); i++) {
HashMap<String, String> map = new HashMap<String, String>();
Element e = (Element) nl.item(i);
newsList.add(map);
}
list=(GridView)getActivity().findViewById(R.id.grid2);
adapter=new HeadlinesAdapter(getActivity(), newsList);
list.setAdapter(adapter);
}
MainActivity =＆GT;
public class MainActivity extends FragmentActivity {
private ViewPager mViewPager;
private MessageLoader mLoader;
private Button mSenderButton, mReceiverButton;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
// We get UI references
mViewPager = (ViewPager) findViewById(R.id.viewPager);
mSenderButton = (Button) findViewById(R.id.sender_button);
mReceiverButton = (Button) findViewById(R.id.receiver_button);
// set pager adapter
mViewPager.setAdapter(new MyAdapter(this));
// set receiver button listener
mReceiverButton.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
mViewPager.setCurrentItem(1);
}
});
mSenderButton.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
mViewPager.setCurrentItem(0);
}
});
}
private class MyAdapter extends FragmentPagerAdapter{
private Context mContext;
private String[] frags = {Fragment1.class.getName(), Fragment2.class.getName()};
public MyAdapter(FragmentActivity activity) {
super(activity.getSupportFragmentManager());
mContext = activity;
}
@Override
public Object instantiateItem(ViewGroup container, int position) {
Fragment frag = (Fragment) super.instantiateItem(container, position);
if(frag instanceof MessageLoader){
mLoader = (MessageLoader) frag;
}
return frag;
}
@Override
public Fragment getItem(int pos) {
return Fragment.instantiate(mContext, frags[pos]);
}
@Override
public int getCount() {
return frags.length;
}
}
}
答案 0 :(得分：1)
这与您的其他问题有关：
他们以任何方式在应用程序时停止执行Fragment2 startup.I必须在我滑到Fragment2
时启动它
不，你不应该首先尝试这样做。 ViewPager需要第二个Fragment（尚未显示）才能处于良好状态，以便用户可以选择立即滑动到它。如果不构建Fragment那么用户体验将会很差，特别是在您解析主Url线程上UI的某些xml时。如果你想提高应用程序的速度并避免可能的ANR，你应该真的看看在后台线程上进行xml解析。
我想在启动时调用'function1'，只在我调用'function2'时调用'function1' 滑动到Fragment2
保持Fragment 1现在（调用您希望调用的方法），然后使用OnPageChangeListener上的ViewPager。我假设您使用自定义FragmentPagerAdapter，因此您可以获得对第二个Fragment的引用，并直接调用populate_listview()方法：
@Override
public void onPageScrolled(int position, float positionOffset, int positionOffsetPixels) {
Fragment2 = (Fragment2) getSupportFragmentManager()
.findFragmentByTag(
"android:switcher:" + R.id.viewPager + ":" + 1);
if (fragment != null) {
fragment.populate_listview();// remove the call from onViewCreated
}
}
但这只是一个黑客。您要做的是使用后台线程（AysncTask或普通线程）进行长时间操作。看看这个blog entry。