希望我的所有专家都很好。 Buddy我陷入了一个非常简单的代码。实际上我必须插入一个表单,然后从中获取值以将邮件发送给填写表单的用户。所有值都插入到数据库中,并且还从数据库中获取但邮件未发送。一天前,同样的代码正在发送邮件。但今天它不发送邮件。请帮我解决这个问题。
<?php
require("dbconnect.php");
require("DBConnection.php");
session_start();
if(isset($_POST['postadd'])){
$title = $_POST['adtitle'];
$area = $_POST['area'];
$addesc = $_POST['addesc'];
$email = $_POST['email'];
$showemail = $_POST['showemail'];
$userpic = ($_FILES['pic1']['tmp_name']);
$compath = "UploadPictures/".md5($_FILES['pic1']['name']);
$comFileType=$_FILES['pic1']['type'];
$comFileSize=$_FILES['pic1']['size'];
$comFileSize=$comFileSize/1024;
if($comFileSize<1000)
{
$arrFileType=array("image/jpeg","image/png","image/gif","image/bmp");
if(in_array($comFileType,$arrFileType))
{
move_uploaded_file($userpic,$compath);
}
else
{
("Invalid Image Format");
}
}
else
{
("File Size Error");
}
$pic2 = ($_FILES['pic2']['tmp_name']);
$compath2 = "UploadPictures/".md5($_FILES['pic2']['name']);
$comFileType2=$_FILES['pic2']['type'];
$comFileSize2=$_FILES['pic2']['size'];
$comFileSize2=$comFileSize2/1024;
if($comFileSize2<1000)
{
$arrFileType2=array("image/jpeg","image/png","image/gif","image/bmp");
if(in_array($comFileType2,$arrFileType2))
{
move_uploaded_file($pic2,$compath2);
}
else
{
("Invalid Image Format");
}
}
else
{
("File Size Error");
}
$pic3 = ($_FILES['pic3']['tmp_name']);
$compath3 = "UploadPictures/".md5($_FILES['pic2']['name']);
$comFileType3=$_FILES['pic3']['type'];
$comFileSize3=$_FILES['pic3']['size'];
$comFileSize3=$comFileSize3/1024;
if($comFileSize3<1000)
{
$arrFileType3=array("image/jpeg","image/png","image/gif","image/bmp");
if(in_array($comFileType3,$arrFileType3))
{
move_uploaded_file($pic3,$compath3);
}
else
{
("Invalid Image Format");
}
}
else
{
("File Size Error");
}
$pic4 = ($_FILES['pic4']['tmp_name']);
$compath4 = "UploadPictures/".md5($_FILES['pic4']['name']);
$comFileType4=$_FILES['pic4']['type'];
$comFileSize4=$_FILES['pic4']['size'];
$comFileSize4=$comFileSize4/1024;
if($comFileSize4<1000)
{
$arrFileType4=array("image/jpeg","image/png","image/gif","image/bmp");
if(in_array($comFileType4,$arrFileType4))
{
move_uploaded_file($pic4,$compath4);
}
else
{
("Invalid Image Format");
}
}
else
{
("File Size Error");
}
$agree = $_POST['checkbox'];
$subcat = $_SESSION['subcat'];
$cat = $_SESSION['cat'];
$rand = rand();
$datecreated = date("Y-m-d h:i:s");
$obj = new DBConnection();
$arr_Field = array("title","location","post","email","radio","pic1","pic2","pic3","pic4","agree","cat","subcat","random","datecreated");
$arr_values = array("$title","$area","$addesc","$email","$showemail","$compath","$compath2","$compath3","$compath4","$agree", "$cat", "$subcat" ,"$rand","$datecreated");
$obj->InsertRecord("ads",$arr_Field,$arr_values) or die (mysql_error());
$object = new DBConnection();
$condition = "ORDER BY id DESC LIMIT 1";
$selquery = $object->SelectRecord(array("*"),"ads","$condition") or die(mysql_error());
while($get = mysql_fetch_array($selquery)){
$email = $get['email'];
$id = $get['id'];
}
//echo $email;
//exit();
$to = $email;
$subject = "Admin";
$message = "
<html>
<head>
<title>Admin</title>
</head>
<body>
<p>Please Click on this Link to verify your post</p>
<p><a href='http://almughnisolutions.com/almughniclassified/summary.php?summary=".$id."'>http://almughnisolutions.com/almughniclassified/summary.php?summary=".$id."</a></p>
</body>
</html>
";
// Always set content-type when sending HTML email
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
// More headers
$headers .= 'From: <admin@almughniclassfied.com>' . "\r\n";
mail($to,$subject,$message,$headers) or die("Mail Cannot sent");
//header("Location:verifyadd.php");
}
?>
答案 0 :(得分:1)
这可能是一个安全的假设,你的代码不应该受到责备。如果SMPT服务器的行为正确,那么粗略地回顾一下它似乎很有用。我建议测试服务器。有一些基于Web的工具可以做到这一点:
https://www.wormly.com/test_smtp_server
如果需要在内部完成某些操作,您也可以使用telnet从您的机器进行测试:
http://technet.microsoft.com/en-us/library/aa995718%28v=exchg.65%29.aspx