This question讨论了JFrame扩展到Windows任务栏的已知错误。 An answer链接到错误报告(具有各种重复项)并提供解决方法。我发现问题也适用于JDialogs。 JFrame解决方法不适用。是否有类似的解决方法使JDialogs在Windows上表现自己?
示例代码:
import javax.swing.*;
public class Demo extends JDialog {
public Demo() {
setSize(250,12500);
setVisible(true);
}
public static void main(String[] args) {
new Demo();
}
}
修改
看起来这不会在JDK中修复。 This bug report结束时评论说“如果开发人员想让他们的窗口在屏幕上完全可见,他们应该考虑自己检查屏幕插图 [如下面的解决方案] ,然后重新开始以不同的方式布局它们的组件,或者在调用pack()之后手动重新调整窗口大小,或者使用支持screen-insets的布局管理器 [与BorderLayout和GridBagLayout等更常见的不同。“
答案 0 :(得分:5)
这基本上可以确保对话框“适合”指定的屏幕,方法是将其移动到指定设备的范围内并缩小它,使其左下边缘在指定设备的范围内。 / p>
这会查看设备边界和插图,以计算对话框可以驻留的“安全”区域。
public class TestScreenSize {
public static void main(String[] args) {
new TestScreenSize();
}
public TestScreenSize() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException ex) {
} catch (InstantiationException ex) {
} catch (IllegalAccessException ex) {
} catch (UnsupportedLookAndFeelException ex) {
}
Test test = new Test();
test.setLayout(new BorderLayout());
test.setVisible(true);
System.exit(0);
}
});
}
public class Test extends JDialog {
public Test() {
setModal(true);
setLocation(0, 0);
setSize(2000, 2000);
}
@Override
public void setBounds(int x, int y, int width, int height) {
Rectangle bounds = getSafeScreenBounds(new Point(x, y));
if (x < bounds.x) {
x = bounds.x;
}
if (y < bounds.y) {
y = bounds.y;
}
if (width > bounds.width) {
width = (bounds.x + bounds.width) - x;
}
if (height > bounds.height) {
height = (bounds.y + bounds.height) - y;
}
super.setBounds(x, y, width, height);
}
}
public static Rectangle getSafeScreenBounds(Point pos) {
Rectangle bounds = getScreenBoundsAt(pos);
Insets insets = getScreenInsetsAt(pos);
bounds.x += insets.left;
bounds.y += insets.top;
bounds.width -= (insets.left + insets.right);
bounds.height -= (insets.top + insets.bottom);
return bounds;
}
public static Insets getScreenInsetsAt(Point pos) {
GraphicsDevice gd = getGraphicsDeviceAt(pos);
Insets insets = null;
if (gd != null) {
insets = Toolkit.getDefaultToolkit().getScreenInsets(gd.getDefaultConfiguration());
}
return insets;
}
public static Rectangle getScreenBoundsAt(Point pos) {
GraphicsDevice gd = getGraphicsDeviceAt(pos);
Rectangle bounds = null;
if (gd != null) {
bounds = gd.getDefaultConfiguration().getBounds();
}
return bounds;
}
public static GraphicsDevice getGraphicsDeviceAt(Point pos) {
GraphicsDevice device = null;
GraphicsEnvironment ge = GraphicsEnvironment.getLocalGraphicsEnvironment();
GraphicsDevice lstGDs[] = ge.getScreenDevices();
ArrayList<GraphicsDevice> lstDevices = new ArrayList<GraphicsDevice>(lstGDs.length);
for (GraphicsDevice gd : lstGDs) {
GraphicsConfiguration gc = gd.getDefaultConfiguration();
Rectangle screenBounds = gc.getBounds();
if (screenBounds.contains(pos)) {
lstDevices.add(gd);
}
}
if (lstDevices.size() > 0) {
device = lstDevices.get(0);
} else {
device = ge.getDefaultScreenDevice();
}
return device;
}
}
答案 1 :(得分:1)
好的,下面没有魔法,但是像max(a,b)一样简单:
import java.awt.Dimension;
import java.awt.Frame;
import java.awt.Toolkit;
import javax.swing.JDialog;
public class Demo extends JDialog {
public Demo() {
super((Frame)null, "Demo" );
setDefaultCloseOperation( DISPOSE_ON_CLOSE );
Dimension screenSize = Toolkit.getDefaultToolkit().getScreenSize();
int width = Math.min( 250, screenSize.width );
int height = Math.min( 12_500, screenSize.height );
pack();
setSize( width, height );
setVisible( true );
}
public static void main( String[] args ) {
new Demo();
}
}