Question

这是我在这里的第一篇文章。我有一张桌子，我从facebook页面收集id。我有另一张表，我收集有关这些页面的所有信息。我的问题是：如何通过json_decode（graph.facebook.com/id）将第一个表中的id传递给第二个表？我不知道如何制作它。谢谢大家，我很抱歉我的英语不好。这是我的add.php： `

if (!isset($addid))
{
?>
<form action="add.php">
Page/App ID: <input type="text" name="id">
<input type="submit" value="Submit">
<form>
<?php
 }
else
{
$url = "http://graph.facebook.com/" . $addid;
$geturl = file_get_contents($url);
$info = json_decode($geturl);
$pagetype = $info->icon_url;
if ($pagetype == '')
{
    $id = $info->id;
    $name = mysql_real_escape_string($info->name);
    $website = mysql_real_escape_string($info->website);
    $username = mysql_real_escape_string($info->username);
    $description = mysql_real_escape_string($info->description);
    $about = mysql_real_escape_string($info->about);
    $talking_about_count = $info->talking_about_count;
    if ($talking_about_count == '') { $talking_about_count = 0; }
    $category = mysql_real_escape_string($info->category);
    $link = mysql_real_escape_string($info->link);
    $likes = $info->likes;
    $date = date("Y-m-d H:i:s");
    if ($likes == '') { $likes == 0; }
    ?>
    <form action="add.php">
        Page/App Name/ID: <input type="text" name="id">
        <input type="submit" value="Submit">
        <form>
    <br>
    <br>
    <br>
    <div>
    Info about this page: <?php echo $name . " (" . $id . ")"; ?> <br><br>
    ID: <?php echo $id; ?> <br>
    Name: <?php echo $name; ?> <br>
    Website: <?php echo $website; ?> <br>
    Username: <?php echo $username; ?> <br>
    Description: <?php echo $description; ?> <br>
    About: <?php echo $about; ?> <br>
    Talking about count: <?php echo $talking_about_count; ?> <br>
    Category: <?php echo $category; ?> <br>
    Link: <?php echo $link; ?> <br>
    Likes: <?php echo $likes ?> <br>
    Image: <img src="http://graph.facebook.com/<?php echo $id?>/picture">          <br><br>
    Added on: <?php echo $date; ?><br><br><br>
    <br>
    <br>
    Adding info in database...
    <br>
    <?php
        $query = "INSERT INTO pages (id, name, website, username, description, about, talking_about_count, category, link, likes, addedon) VALUES ($id, '$name', '$website', '$username', '$description', '$about', $talking_about_count, '$category', '$link', $likes, $date)";
        mysql_query($query);
        echo "Done";
                    echo "</div";
    ?>
`

从一个表中获取数据并使用mysql放入第二个表中？

0 个答案: