我正在构建一个报告,输出应该像(例子):
['11/2012', 5, 2, 0]
['10/2012', 7, 1, 0]
['09/2012', 2, 3, 0]
['08/2012', 0, 0, 1]
['07/2012', 0, 2, 1]
['06/2012', 2, 1, 0]
['05/2012', 3, 1, 1]
['04/2012', 2, 2, 1]
['03/2012', 5, 0, 0]
['02/2012', 7, 1, 0]
['01/2012', 2, 0, 0]
['12/2011', 3, 0, 1]
对于月份部分,我需要获得实际的月份而不是一年前的列表。我用这段代码完成了这个:
<%
DataAtual_PeriodoInicial= Now
DataFinal_PeriodoInicial= DateAdd("m", -13, Now)
DO WHILE Datediff("m", DataAtual_PeriodoInicial, DataFinal_PeriodoInicial) <> 0
%>
['<% Response.Write(Right("0" & Month(DataAtual_PeriodoInicial), 2)) %>/<% Response.Write(Year(DataAtual_PeriodoInicial)) %>', X, Y, Z]<br>
<%
DataAtual_PeriodoInicial= DateAdd("m", -1, DataAtual_PeriodoInicial)
LOOP
%>
所以这就产生了:
['11/2012', X, Y, Z]
['10/2012', X, Y, Z]
['09/2012', X, Y, Z]
['08/2012', X, Y, Z]
['07/2012', X, Y, Z]
['06/2012', X, Y, Z]
['05/2012', X, Y, Z]
['04/2012', X, Y, Z]
['03/2012', X, Y, Z]
['02/2012', X, Y, Z]
['01/2012', X, Y, Z]
['12/2011', X, Y, Z]
现在我必须抛出一些数字而不是X,Y和Z.我有一个包含数据的表:
11 2012 X
10 2012 X
10 2012 X
10 2012 X
10 2012 Y
10 2012 Y
10 2012 Z
10 2012 Z
10 2012 Z
9 2012 X
9 2012 X
9 2012 X
9 2012 Y
9 2012 Z
9 2012 Z
8 2012 X
8 2012 X
8 2012 Y
8 2012 Y
8 2012 Y
8 2012 Y
8 2012 Y
...
我从这个选择开始:
SELECT
datepart(month,SentDate) AS Mes,
datepart(year,SentDate) AS Ano,
EventType
FROM
SomeTable
ORDER BY
SentDate DESC
我试过了一些小组,但没有过了。我需要某种伯爵吗?和?我怎样才能完成这个问题顶部的输出?
谢谢!
答案 0 :(得分:2)
试试这个
SELECT
datepart(month,SentDate) AS Mes,
datepart(year,SentDate) AS Ano,
sum(CASE WHEN EventType = 'X' THEN 1 ELSE 0 END ) X,
sum(CASE WHEN EventType = 'Y' THEN 1 ELSE 0 END ) Y,
sum(CASE WHEN EventType = 'Z' THEN 1 ELSE 0 END ) Z
FROM
SomeTable
GROUP BY
datepart(month,SentDate),
datepart(year,SentDate)
ORDER BY
Ano DESC,
Mes DESC
SentDate DESC
http://sqlfiddle.com/#!3/93a11/23/0
演示您也可以使用PIVOT表
SELECT * FROM
(
SELECT
datepart(month,SentDate) AS Mes,
datepart(year,SentDate) AS Ano,
EventType
FROM
SomeTable
) grouped
PIVOT (COUNT(eventType) for EventType in ([X],[Y],[Z])) AS pivoted
ORDER BY
Ano DESC,
Mes DESC
演示