Question

我有一个这样的数据库：

  ----------------------------------------------
  | ID |  Time  |    Typeop     |   Operator   |
  ----------------------------------------------
  |  1 |  10:01 |  withdrawal   |     John     |
  |  2 |  10:01 |  deposit      |     Mike     |
  |  3 |  10:01 |  deposit      |     Andrew   |
  |  4 |  10:02 |  check        |     John     |
  |  5 |  10:02 |  withdrawal   |     Simon    |
  |  6 |  10:03 |  withdrawal   |     Dorothy  |

通过以下查询我选择最后三行：

 SELECT * from mytable ORDER BY ID DESC LIMIT 0,3

问题：我需要在PHP脚本中“回显”我脚本不同位置的最后三个运算符以及不同的顺序，因此我将每个名称分配给另一个变量。在这个例子中：

$ name0 = Dorothy
$ name1 = Simon
$ name3 = John

所以我可以将它们（例如）放在这样的文本中......“多萝西是最后一个在西蒙之后进行手术的人。约翰今天在三人面前停了下来......”

提前预订

Answer 1

将结果放入数组并使用键0，1和2来定位它们：

$operators = array();

$result = $mysqli->query("SELECT Operator from mytable ORDER BY ID DESC LIMIT 0,3");

if($result)
{
    while($row = $result->fetch_assoc())
    {
        $operators[] = $row['Operator'];
    }
}

if(count($operators) >= 3)
{
    echo htmlentities($operators[0]) . " has been the last to make an operation after " . htmlentities($operators[1]) . ". " . htmlentities($operators[2]) . " today stopped before them";
}

此示例使用MySQLi并假设始终有3条记录。

编辑：任何MySQL库的原理都是一样的，例如使用原生的mysql_ *库：

$operators = array();

$result = mysql_query("SELECT Operator from mytable ORDER BY ID DESC LIMIT 0,3");

if($result)
{
    while($row = mysql_fetch_assoc($result))
    {
        $operators[] = $row['Operator'];
    }
}

if(count($operators) >= 3)
{
    echo htmlentities($operators[0]) . " has been the last to make an operation after " . htmlentities($operators[1]) . ". " . htmlentities($operators[2]) . " today stopped before them";
}

Answer 2

//从表
收集数据

$data = mysql_query("SELECT * from mytable ORDER BY ID DESC LIMIT 0,3") or  die(mysql_error());

//将＆＃34; mytable＆＃34;信息到$ info数组

 $info = mysql_fetch_array( $data );

//打印信息

while($info = mysql_fetch_array( $data )) 
{ 
   echo "<b>Operator:</b> ".$info['Operator'] . " "; 
}

Answer 3

您需要将结果存储在独立的php数组中

$ops = array();
$result = mysql_query("SELECT Operator from mytable ORDER BY ID DESC LIMIT 0,3");
$i = 0;
if($result)
{
    while($row = mysql_fetch_assoc($result))        
        $ops[$i++] = $row[0];        
}

此处$row每次都会更改，它只会保留最新值，但$ops会存储所有

现在你可以在任何地方使用这个数组作为你想要的输出（直到你改变数组$ops），例如。

$st = $ops[0]." has been the last to make an operation after ".$ops[1].". ".$ops[2]." today stopped before the three...";
echo $st;

处理列的单数记录

3 个答案: