mysql查询帮助进行层次结构显示

Question

我有一张桌子：

id  type_name               type_reportToId 
1   Administrator               0   
2   Guest   GUEST               1   
3   Landlord                    1   
4   Property Manager            3   
13  Manager Manager             3   
14  Asst. Property Manager     13   

我需要“报告到层次结构”的ID为14号的结果。例如：id 14必须报告13,13必须报告3,3必须报告1 ...喜欢明智。我需要在mysql中查询。有谁能够帮我 ？

Answer 1

您最好在应用程序逻辑中而不是在查询中执行此操作。

伪代码

query=SELECT id, type_name, type_reportToId FROM table ORDER BY id ASC, report_toId ASC

// loop through rows
currentParent = 0
processed = 0
hierarachyLevel = 0
while ( processed < foundrows ) 
{
     while ( row = fetchrow( dbResult ) )
    {
         if ( row[type_reportToId] == currentParent )
         {
             resultHierarchy[hierarchyLevel] = row
             currentParent = row[id]
             processed++
             hierarchyLevel++
             dataseek( dbResult, 0 )
             break
         }
   }

}