Question

我需要交叉表或数据透视表按选择日期时间。

表格文件

EmpNo     ChkDate                    ChkIn
00001     2012-10-10 00:00:00.000    2012-10-10 07:22:00.000
00002     2012-10-10 00:00:00.000    2012-10-10 07:30:00.000
00001     2012-10-11 00:00:00.000    2012-10-11 07:13:00.000
00002     2012-10-11 00:00:00.000    2012-10-11 07:34:00.000
00001     2012-10-12 00:00:00.000    2012-10-12 07:54:00.000
00002     2012-10-12 00:00:00.000    2012-10-12 07:18:00.000

我试过以下

SELECT tf.EmpNo,tf.ChkDate,tf.ChkIn
FROM (SELECT EmpNo,ChkDate,ChkIn
        ,ROW_NUMBER() OVER(PARTITION BY EmpNo ORDER BY ChkDate) as tfNum
        FROM filesTA) AS tf
    PIVOT(MIN(ChkDate) FOR tfNum IN ('2012-10-10'))
WHERE tf.ChkDate Between '2012-10-10' and '2012-10-12'

但是得到以下错误

Incorrect syntax near 'PIVOT'. You may need to set the compatibility
level of the current database to a higher value to enable this feature.
See help for the SET COMPATIBILITY_LEVEL option of ALTER DATABASE.

期望输出：

EmpNo     10     11     12
00001     07:22  07:13  07:54
00002     07:30  07:34  07:18

我开始学习枢轴和交叉表。请帮我解决问题。

Answer 1

如果您无法使用PIVOT函数，则可以使用带有CASE语句的聚合函数：

select empno,
  max(case when datepart(d, chkdate) = 10 
        then convert(char(5), ChkIn, 108) end) [10],
  max(case when datepart(d, chkdate) = 11 
        then convert(char(5), ChkIn, 108) end) [11],
  max(case when datepart(d, chkdate) = 12
        then convert(char(5), ChkIn, 108) end) [12]
from filesTA
where ChkDate Between '2012-10-10' and '2012-10-12'
group by empno

请参阅SQL Fiddle with Demo

如果您有权访问PIVOT，那么您的语法将是：

select empno, [10], [11], [12]
from
(
  select empno, datepart(d, chkdate) chkdate, 
    convert(char(5), ChkIn, 108) chkin
  from filesTA
) src
pivot
(
  max(chkin)
  for chkdate in ([10], [11], [12])
) piv

请参阅SQL Fiddle with Demo

Answer 2

如果您需要在兼容级别低于90的数据库上使用PIVOT，则无效。

阅读此ALTER DATABASE Compatibility Level

修改后的DATABASE兼容级别后，您的查询将如此

;WITH cte AS
 (
  SELECT EmpNo, CAST(ChkIn AS time) AS ChkIn, DATEPART(mm, ChkDate) as mm_ChkDate
  FROM filesTA
  WHERE ChkDate Between '2012-10-10' and '2012-10-12'
  )
SELECT EmpNo, [10], [11], [12] FROM cte  
PIVOT(
MIN(ChkIn) FOR cte.mm_ChkDate IN ([10], [11], [12])) x

我如何通过日期时间PIVOT TABLE或CrossTab？

2 个答案: