我研究了这个,但我使用的代码似乎都没有用。南非身份证号码包含出生日期和性别。我想要的只是当他们的ID号被输入到输入字段时输入该信息并验证它,最好是在jQuery或javascript中
感谢任何帮助,
的Dawid
答案 0 :(得分:10)
您可以使用Koenyn的正则表达式验证,但不确定输入中的一位数字(0-9?)如何代表性别,但基于您提供的this tool和David Russell的Using Javascript to validate South African ID Numbers,这是一个未经测试的尝试:
更新1: 在关注此主题What is a South African ID number made up of?之后,我更新了我的实施,以包括性别和公民身份测试。
更新2:
忘记在日期字符串id_month + 1
中包装月份数增量fullDate
,使用Dawid修正更新解决方案。
HTML标记:
<div id="error"></div>
<form id="idCheck">
<p>Enter the ID Number: <input id="idnumber" /> </p>
<p> <input type="submit" value="Check" /> </p>
</form>
<div id="result"> </div>
<强>的Javascript 强>:
function Validate() {
// first clear any left over error messages
$('#error p').remove();
// store the error div, to save typing
var error = $('#error');
var idNumber = $('#idnumber').val();
// assume everything is correct and if it later turns out not to be, just set this to false
var correct = true;
//Ref: http://www.sadev.co.za/content/what-south-african-id-number-made
// SA ID Number have to be 13 digits, so check the length
if (idNumber.length != 13 || !isNumber(idNumber)) {
error.append('<p>ID number does not appear to be authentic - input not a valid number</p>');
correct = false;
}
// get first 6 digits as a valid date
var tempDate = new Date(idNumber.substring(0, 2), idNumber.substring(2, 4) - 1, idNumber.substring(4, 6));
var id_date = tempDate.getDate();
var id_month = tempDate.getMonth();
var id_year = tempDate.getFullYear();
var fullDate = id_date + "-" + (id_month + 1) + "-" + id_year;
if (!((tempDate.getYear() == idNumber.substring(0, 2)) && (id_month == idNumber.substring(2, 4) - 1) && (id_date == idNumber.substring(4, 6)))) {
error.append('<p>ID number does not appear to be authentic - date part not valid</p>');
correct = false;
}
// get the gender
var genderCode = idNumber.substring(6, 10);
var gender = parseInt(genderCode) < 5000 ? "Female" : "Male";
// get country ID for citzenship
var citzenship = parseInt(idNumber.substring(10, 11)) == 0 ? "Yes" : "No";
// apply Luhn formula for check-digits
var tempTotal = 0;
var checkSum = 0;
var multiplier = 1;
for (var i = 0; i < 13; ++i) {
tempTotal = parseInt(idNumber.charAt(i)) * multiplier;
if (tempTotal > 9) {
tempTotal = parseInt(tempTotal.toString().charAt(0)) + parseInt(tempTotal.toString().charAt(1));
}
checkSum = checkSum + tempTotal;
multiplier = (multiplier % 2 == 0) ? 1 : 2;
}
if ((checkSum % 10) != 0) {
error.append('<p>ID number does not appear to be authentic - check digit is not valid</p>');
correct = false;
};
// if no error found, hide the error message
if (correct) {
error.css('display', 'none');
// clear the result div
$('#result').empty();
// and put together a result message
$('#result').append('<p>South African ID Number: ' + idNumber + '</p><p>Birth Date: ' + fullDate + '</p><p>Gender: ' + gender + '</p><p>SA Citizen: ' + citzenship + '</p>');
}
// otherwise, show the error
else {
error.css('display', 'block');
}
return false;
}
function isNumber(n) {
return !isNaN(parseFloat(n)) && isFinite(n);
}
$('#idCheck').submit(Validate);
答案 1 :(得分:5)
这是我们公司的验证正则表达式:
string IdExpression = @"(?<Year>[0-9][0-9])(?<Month>([0][1-9])|([1][0-2]))(?<Day>([0-2][0-9])|([3][0-1]))(?<Gender>[0-9])(?<Series>[0-9]{3})(?<Citizenship>[0-9])(?<Uniform>[0-9])(?<Control>[0-9])";
就使用正则表达式而言,它非常简单 http://www.w3schools.com/jsref/jsref_obj_regexp.asp
答案 2 :(得分:0)
您可以使用jQuery插件。请查看http://www.verifyid.co.za/jqueryid