Question

我的XML的一部分看起来像这样：

<IOConfig>
  <Packet Name="PacketOut" RemoteAddress="10.0.2.223" RemotePort="2020" NetworkInterface="ETH0">
    <Signal Type="float" Name="x_out" Unit="m/s" Routing="" UnityObject="CraneBoom" UnityName="Out" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="y_out" Unit="m/s" Routing="" UnityObject="CraneBoom" UnityName="Out" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="z_out" Unit="m/s" Routing="" UnityObject="CraneBoom" UnityName="Out" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="alpha_out" Unit="m/s" Routing="" UnityObject="CraneBoom" UnityName="Out" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="theta_out" Unit="m/s" Routing="" UnityObject="CraneBoom" UnityName="Out" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="phi_out" Unit="m/s" Routing="" UnityObject="CraneBoom" UnityName="Out" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="x_out1" Unit="m/s" Routing="" UnityObject="CraneSlewing" UnityName="Out1" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="y_out1" Unit="m/s" Routing="" UnityObject="CraneSlewing" UnityName="Out1" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="z_out1" Unit="m/s" Routing="" UnityObject="CraneSlewing" UnityName="Out1" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="alpha_out1" Unit="m/s" Routing="" UnityObject="CraneSlewing" UnityName="Out1" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="theta_out1" Unit="m/s" Routing="" UnityObject="CraneSlewing" UnityName="Out1" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="phi_out1" Unit="m/s" Routing="" UnityObject="CraneSlewing" UnityName="Out1" NetworkConvert="1"></Signal>
  </Packet>
  <Packet Name="PacketIn" LocalPort="2021" NetworkInterface="ETH0">
    <Signal Type="float" Name="x_in" Unit="m/s" Routing="" UnityObject="CraneBoomCrash" UnityName="collider1" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="y_in" Unit="m/s" Routing="" UnityObject="CraneBoomCrash" UnityName="collider1" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="z_in" Unit="m/s" Routing="" UnityObject="CraneBoomCrash" UnityName="collider1" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="alpha_in" Unit="m/s" Routing="" UnityObject="CraneBoomCrash" UnityName="collider1" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="theta_in" Unit="m/s" Routing="" UnityObject="CraneBoomCrash" UnityName="collider1" NetworkConvert="1"></Signal>
    <Signal Type="float" Name="phi_in" Unit="m/s" Routing="" UnityObject="CraneBoomCrash" UnityName="collider1" NetworkConvert="1"></Signal>
  </Packet>
</IOConfig>

所需的输出为：Out，Out1，collider1。

也就是说，不应打印UnityName的重复值。可以这样做吗？

代码剪断了读取UnityName的重复值：

public class XMLStringReader : MonoBehaviour
{
    public string slectedItem;
    private bool editing = false;

    public string signalsa;
    public XmlReaderSettings settings;

    void OnGUI ()
    {
        if ( GUILayout.Button(slectedItem))
        {
            editing = true;
        }

        XmlReaderSettings settings = new XmlReaderSettings();
        settings.IgnoreWhitespace = true;
        settings.IgnoreComments = true;

        using ( XmlReader reader = XmlReader.Create("D://Docs/Unity3D/cdp/UDPApplication/Components/UDPIOServer.xml", settings) ) 
        {
            while ( reader.Read() ) 
            {
                if ( reader.NodeType == XmlNodeType.Element ) 
                {
                    if ( reader.HasAttributes ) 
                    {
                        if ( reader.GetAttribute("UnityName") != null ) 
                        {
                            signalsa = reader.GetAttribute("UnityName");
                            string [] signalsCDP = {signalsa};

                            if (editing)
                            {
                                for(int i =0; i < signalsCDP.Length; i++) 
                                {
                                    if (GUILayout.Button(signalsCDP[i]))
                                    {
                                        slectedItem = signalsCDP[i];
                                        editing = false;
                                        print(signalsCDP[i].ToString());
                                    }
                                }
                            }
                        }
                    }
                }
            }
        }
    }
}

Answer 1

您可以使用LINQ to XML完成任务：

XElement x = XElement.Load("File containing your xml");
var list = x.Descendants("Signal")
            .Where(d => d.HasAttributes && d.Attribute("UnityName") != null)
            .Select(d => d.Attribute("UnityName").Value)
            .Distinct();
foreach (string s in list)
    Console.WriteLine(s);

Answer 2

迭代所有值，并使用包含检查将它们添加到List / Dictionary / Array / Whatever。之后打印收集的值。

以下是解决方案：

    internal static void PrintAttributeValues(XDocument scr)
    {
        List<string> values = new List<string>();
        foreach (XElement elem in scr.Descendants("Signal"))
        {
            if (!values.Contains(elem.Attribute("UnityName").Value))
            {
                values.Add(elem.Attribute("UnityName").Value);
            }
        }

        for (int j = 0; j < values.Count; j++)
        {
            Console.WriteLine(values[j]);
        }
    }

Answer 3

另一种方法是为程序化方法之外的任何XML定义 XML Schema 。 XML Schema 确保XML的合规性。

XML Schema描述了XML文档的结构。

查看以下参考资料：

Answer 4

只需创建一个包含不同值的集合。然后检查下一个属性值是否已在该集合中。如果没有，请将其添加到集合中并执行您需要的任何操作。

List<string> values = new List<string>();

using (XmlReader reader = XmlReader.Create("your path", settings)) 
{
    while (reader.Read()) 
    {
        if (reader.NodeType == XmlNodeType.Element) 
        {
            if (reader.HasAttributes) 
            {
                if (reader.GetAttribute("UnityName") != null) 
                {
                    signalsa = reader.GetAttribute("UnityName");
                    if (!values.Contains(signalsa))
                    {
                        values.Add(signalsa);
                        //rest of your code goes here...
                    }
                }
            }
        }
    }
}

如何在xml c＃中避免重复属性？

4 个答案: