Question

这似乎是一个本来应该已经回答的问题，但我似乎找不到令人满意的东西。无论如何，我需要从函数返回看起来像：

{ {"foo", "bar"}, {"baz", "foo"}, {"foo", "bar"} }

我熟悉argv的使用，我理解它的类型意味着什么，但由于某种原因，我无法得到上述表达式的类型。在最里面的部分总会有2个字符串文字，因此我认为像

char **s[2] or char *(*s[2])

应该是我所追求的但是由于某种原因，无论我在尝试迭代并使用printf时尝试的排列，我总是最终得到段错误。此外，编译器经常抱怨不兼容的指针类型，多余的元素和太多的大括号。这是当前的代码：

 char *(*s[2]) = { {"foo", "bar"}, {"baz", "spam"}, {"eggs", "ham"} };

Answer 1

你很亲密。

#include <stdio.h>

int main()
{

    char* s[][2] = { {"foo", "bar"}, {"baz", "spam"}, {"eggs", "ham"} };

    for( int i = 0; i < 3; i++ )
    {
        for(int j = 0; j < 2; j ++)
        {
            printf("%s ",s[i][j]);
        }
    }

}

以上版画：foo bar baz spam eggs ham

Answer 2

很简单

char *s[3][2] ={ {"foo", "bar"}, {"baz", "spam"}, {"eggs", "ham"} };

一点解释：

char *s ; //   |s| ---> "Only one char array or string"
                          ______
char *s[] ; //  |s| ---> |_s[0]_|--> 1st pointer to char array --> "1st string"
                         |_s[1]_|--> 2nd pointer to char array --> "2nd string"
                         |_s[2]_|--> 3rd pointer to char array --> "3rd string"

                          ___                                __
char *s[][] ;// |s| ---> |___|--> 1st pointer to pointer -->|__|-->"1st string"                                                                  
                                                            |__|-->"2nd string"                                                                           
                         ____                                __            
                         |___|--> 2nd pointer to pointer -->|__|-->"1st string"                                                                  
                                                            |__|-->"2nd string"
                         ____                                __             
                         |___|--> 3rd pointer to pointer -->|__|-->"1st string"                                                                  
                                                            |__|-->"2nd string"

Answer 3

char *s[][2] = { {"foo", "bar"}, {"baz", "spam"}, {"eggs", "ham"} };


cout<<s[1][0];

会打印baz

嵌套的C数组指针类型

3 个答案: