Question

我正在使用使用Doctrine 1.2的遗留系统。我正在尝试创建一个具有多个嵌套条件的查询，如下所示：

SELECT DISTINCT u.*
FROM Users AS u
INNER JOIN Workplaces AS w ON u.workplaceId = w.id
INNER JOIN Municipalities AS m ON u.municipalityId = m.id
INNER JOIN Prefectures AS p ON m.prefectureId = p.id
INNER JOIN Regions AS r ON p.regionId = p.regionId
WHERE (
    (w.shortName = 'ES' AND m.id IN (:esMunicipalityIdArray))
    OR
    (w.shortName = 'JHS' AND m.id IN (:jhsMunicipalityIdArray))
    OR
    (w.shortName = 'ES' AND p.id IN (:esPrefectureIdArray))
    OR
    (w.shortName = 'JHS' AND p.id IN (:jhsPrefectureIDArray))
    OR
    (w.shortName = 'ES' AND r.id IN (:esRegionIdArray))
    OR
    (w.shortName = 'JHS' AND r.id IN (:jhsRegionIdArray))
)

基本上，这里的目标是获取市政府，县（如州或省）或地区的用户的所有姓名（和电子邮件地址）。用户可以选择区域（包含许多县）中的所有用户，或者选择县内的所有用户，或者选择所选城市中的用户。这样，您就可以微调谁收到发送给用户的特定电子邮件。是的，这是相当精细的，是的，它可能有点矫枉过正，但是，嘿，我喜欢挑战。

无论如何，我将如何在Doctrine 1.2中做到这一点？我不确定如何进行这样的嵌套和/或声明。

Answer 1

使用DQL，以下语句将为：

$query = Doctrine_Query::create()
         ->distinct(true)
         ->from("Users u")
         ->innerJoin("u.Workplaces w on u.workplaceId = w.id)
         ->innerJoin("u.Municipalities m on u.workplaceId = m.id)
         ->innerJoin("m.Prefectures p on m.workplaceId = p.id)
         ->innerJoin("p.Regions r on p.workplaceId = r.id)
         ->Where("w.shortName = 'ES' and m.id in ($esMunicipalityIdArray))
         ->orWhere("w.shortName = 'JHS' and m.id in ($jhsMunicipalityIdArray))
         ->orWhere("w.shortName = 'ES' and p.id in ($esPrefectureIdArray))
         ->orWhere("w.shortName = 'JHS' and p.id in ($jhsPrefectureIdArray))
         ->orWhere("w.shortName = 'ES' and r.id in ($esRegionIdArray))
         ->orWhere("w.shortName = 'JHS' and r.id in ($jhsRegionIdArray));

Doctrine 1.2中的嵌套条件语句

1 个答案: