Question

我想让这段代码正常运行。它来自Cryptopp AES

使用点击率
中的AES演示加密和解密

唯一的区别是，我创建了函数 encryptAES 和 decryptAES 并插入了代码。它可以在不创建这些功能的情但现在我收到以下错误： AES / CTR 4不是有效密钥长度，但密钥长度为16位。

string encryptAES(const byte key[], const string& plain, const byte iv[])
{
try
{
    string cipher;

    CTR_Mode< AES >::Encryption e;
    e.SetKeyWithIV(key, sizeof(key), iv);

    // The StreamTransformationFilter adds padding
    //  as required. ECB and CBC Mode must be padded
    //  to the block size of the cipher.
    StringSource(plain, true, 
        new StreamTransformationFilter(e,
            new StringSink(cipher)
        ) // StreamTransformationFilter      
    ); // StringSource
    return cipher;
}
catch(const CryptoPP::Exception& e)
{
    cerr << e.what() << endl;
    return "";
}
}

string decryptAES(const byte key[], const string& cipher, const byte iv[])
{
try
{
    string recovered;

    CTR_Mode< AES >::Decryption d;
    d.SetKeyWithIV(key, sizeof(key), iv);

    // The StreamTransformationFilter removes
    //  padding as required.
    StringSource s(cipher, true, 
        new StreamTransformationFilter(d,
            new StringSink(recovered)
        ) // StreamTransformationFilter
    ); // StringSource
    return recovered;
}
catch(const CryptoPP::Exception& e)
{
    cerr << e.what() << endl;
    return "";
}
}

int main(int argc, char *argv[])
{
AutoSeededRandomPool prng;

byte key[AES::DEFAULT_KEYLENGTH];
prng.GenerateBlock(key, sizeof(key));

byte iv[AES::BLOCKSIZE];
prng.GenerateBlock(iv, sizeof(iv));

string plain = "CTR Mode Test";
string encoded, cipher, recovered;

/*********************************\
\*********************************/

// Pretty print key
encoded.clear();
StringSource(key, sizeof(key), true,
    new HexEncoder(
        new StringSink(encoded)
    ) // HexEncoder
); // StringSource
cout << "key: " << encoded << endl;

// Pretty print iv
encoded.clear();
StringSource(iv, sizeof(iv), true,
    new HexEncoder(
        new StringSink(encoded)
    ) // HexEncoder
); // StringSource
cout << "iv: " << encoded << endl;

/*********************************\
\*********************************/

cout << "plain text: " << plain << endl;
cipher = encryptAES(key, plain, iv);

/*********************************\
\*********************************/

// Pretty print
encoded.clear();
StringSource(cipher, true,
    new HexEncoder(
        new StringSink(encoded)
    ) // HexEncoder
); // StringSource
cout << "cipher text: " << encoded << endl;

/*********************************\
\*********************************/

recovered = decryptAES(key, cipher, iv);
cout << "recovered text: " << recovered << endl;

cin.sync();
cin.get();
}

Answer 1

您的函数正在使用const byte key[]参数，该参数基本上被视为指针。因此sizeof（key）是平台上指针的大小。

string encryptAES(const byte key[], const string& plain, const byte iv[])

// sizeof(key) is the size of a pointer
e.SetKeyWithIV(key, sizeof(key), iv);

您可以使用std::vector<>作为选项，或传递key_len，例如：

string encryptAES(const byte key[], size_t key_len, const string& plain, const byte iv[])

// using key_len for the length of the key
e.SetKeyWithIV(key, key_len, iv);

我希望这是有道理的，因为同样的错误在几个地方。

AES和密钥长度错误

1 个答案: