我知道您可以使用java.net.NetworkInterface->getHardwareAddress()
在Java 6中执行此操作。但是我部署的环境仅限于Java 5.
有人知道如何在Java 5或更早版本中执行此操作吗?非常感谢。
答案 0 :(得分:6)
Java 5中的标准方法是启动本机进程以运行ipconfig
或ifconfig
并解析OutputStream
以获得答案。
例如:
private String getMacAddress() throws IOException {
String command = “ipconfig /all”;
Process pid = Runtime.getRuntime().exec(command);
BufferedReader in = new BufferedReader(new InputStreamReader(pid.getInputStream()));
Pattern p = Pattern.compile(”.*Physical Address.*: (.*)”);
while (true) {
String line = in.readLine();
if (line == null)
break;
Matcher m = p.matcher(line);
if (m.matches()) {
return m.group(1);
}
}
}
答案 1 :(得分:3)
Butterchicken的解决方案没问题,但只适用于英文版的Windows。
更好(独立于语言)的解决方案是匹配MAC地址的模式。在这里,我还要确保此地址具有关联的IP(例如,过滤掉蓝牙设备):
public String obtainMacAddress()
throws Exception {
Process aProc = Runtime.getRuntime().exec("ipconfig /all");
InputStream procOut = new DataInputStream(aProc.getInputStream());
BufferedReader br = new BufferedReader(new InputStreamReader(procOut));
String aMacAddress = "((\\p{XDigit}\\p{XDigit}-){5}\\p{XDigit}\\p{XDigit})";
Pattern aPatternMac = Pattern.compile(aMacAddress);
String aIpAddress = ".*IP.*: (([0-9]*\\.){3}[0-9]).*$";
Pattern aPatternIp = Pattern.compile(aIpAddress);
String aNewAdaptor = "[A-Z].*$";
Pattern aPatternNewAdaptor = Pattern.compile(aNewAdaptor);
// locate first MAC address that has IP address
boolean zFoundMac = false;
boolean zFoundIp = false;
String foundMac = null;
String theGoodMac = null;
String strLine;
while (((strLine = br.readLine()) != null) && !(zFoundIp && zFoundMac)) {
Matcher aMatcherNewAdaptor = aPatternNewAdaptor.matcher(strLine);
if (aMatcherNewAdaptor.matches()) {
zFoundMac = zFoundIp = false;
}
Matcher aMatcherMac = aPatternMac.matcher(strLine);
if (aMatcherMac.find()) {
foundMac = aMatcherMac.group(0);
zFoundMac = true;
}
Matcher aMatcherIp = aPatternIp.matcher(strLine);
if (aMatcherIp.matches()) {
zFoundIp = true;
if(zFoundMac && (theGoodMac == null)) theGoodMac = foundMac;
}
}
aProc.destroy();
aProc.waitFor();
return theGoodMac;
}
答案 2 :(得分:1)
据我所知,没有纯粹的Java 6解决方案。 UUID解决了这个问题,但首先determine OS找出它是否应该运行ifconfig或ipconfig。
答案 3 :(得分:1)
在Linux和Mac OS X Machine上,您可能必须使用ifconfig -a
ipconfig
与windows命令一样。