select
ID,NAME,SEX,RESIDENCE,EMAIL,MOBILE,PASSWORD,MOOD,BIRTHDAY,AVATAR,TYPE,MONEY
from
user
where
ID in
(select USER2 as id from friend where USER1=#userId# and STATUS= 1 union select user1 as id from friend where user2 = #userId# )
select
ID,NAME,SEX,RESIDENCE,EMAIL,MOBILE,PASSWORD,MOOD,BIRTHDAY,AVATAR,TYPE,MONEY
from
user
where
ID in
(select USER2 as id from friend where USER1=#userId# and STATUS= 1)
如果我使用第二个sql就可以了,如果我先使用它会运行error.I认为参数正常,因为两个sql具有相同的参数
org.springframework.jdbc.UncategorizedSQLException: SqlMapClient operation; uncategorized SQLException for SQL []; SQL state [null]; error code [0];
--- The error occurred in com/bit/hapin/dao/activity/activity.xml.
--- The error occurred while applying a parameter map.
--- Check the getInviteFriendForActivity-InlineParameterMap.
--- Check the parameter mapping for the 'userId' property.
--- Cause: java.lang.ArrayIndexOutOfBoundsException: 1; nested exception is com.ibatis.common.jdbc.exception.NestedSQLException:
--- The error occurred in com/bit/hapin/dao/activity/activity.xml.
--- The error occurred while applying a parameter map.
--- Check the getInviteFriendForActivity-InlineParameterMap.
--- Check the parameter mapping for the 'userId' property.
--- Cause: java.lang.ArrayIndexOutOfBoundsException: 1
at org.springframework.jdbc.support.SQLStateSQLExceptionTranslator.translate(SQLStateSQLExceptionTranslator.java:121)
at org.springframework.jdbc.support.SQLErrorCodeSQLExceptionTranslator.translate(SQLErrorCodeSQLExceptionTranslator.java:322)
at org.springframework.orm.ibatis.SqlMapClientTemplate.execute(SqlMapClientTemplate.java:212)
at org.springframework.orm.ibatis.SqlMapClientTemplate.executeWithListResult(SqlMapClientTemplate.java:249)
at org.springframework.orm.ibatis.SqlMapClientTemplate.queryForList(SqlMapClientTemplate.java:296)
at org.springframework.orm.ibatis.SqlMapClientTemplate.queryForList(SqlMapClientTemplate.java:290)
at com.bit.hapin.dao.activity.ActivityDAOImpl.getInviteFriendForActivity(ActivityDAOImpl.java:51)
那我该怎么办?
答案 0 :(得分:0)
第一次查询没有问题。但是,
在第一个查询中:
select USER2 as id from friend ..... select user1 as id from friend ....
哪个表friend
表包含USER2
和user1
列。如果是这样,请确保friend
表中的表列(USER2,user1)。虽然我不知道您的计划要求,但是第二个查询(在您的帖子中)已足够,因为您正在尝试使用union
表single/same
。
您还可以参考:Union on the same table