Question

我无法在数据库中插入新行。我究竟做错了什么？

-(void)InsertRecords{
    fileMgr = [NSFileManager defaultManager];
    sqlite3_stmt *stmt;
    sqlite3 *cruddb;

    const char *sql = "Insert into AllDictionary(id, DeleteFlag, TitleBD, Description, PathToDB, ImageURL) VALUES('565','asasf2','asfas2ff','fggaga2hah','b2bb','aa2aa')";
    NSString *cruddatabase = [self.GetDocumentDirectory stringByAppendingPathComponent:@"MainDb.sqlite"];

    if(!(sqlite3_open([cruddatabase UTF8String], &cruddb)==SQLITE_OK))
    {
        NSLog(@"An error has occured: %s",sqlite3_errmsg(cruddb));
    }
    if (sqlite3_prepare(cruddb, sql, -1, &stmt, NULL)!=SQLITE_OK) {
        NSLog(@"Problem with prepare statement: %s", sqlite3_errmsg(cruddb));
    } else {
        sqlite3_step(stmt);
    }
    sqlite3_finalize(stmt);
    sqlite3_close(cruddb);
}

Answer 1

您的Id类型为int。所以问题在于查询，

const char *sql = "Insert into AllDictionary(id, DeleteFlag, TitleBD, Description, PathToDB, ImageURL) VALUES('565','asasf2','asfas2ff','fggaga2hah','b2bb','aa2aa')";

不要对整数值使用引号来表示字符串值。将查询更改为：

const char *sql = "Insert into AllDictionary(id, DeleteFlag, TitleBD, Description, PathToDB, ImageURL) VALUES(565,'asasf2','asfas2ff','fggaga2hah','b2bb','aa2aa')";

您的方法中存在很多错误，例如，如果未打开db，则始终会执行prepare语句。 Finalize语句将始终使用或不执行prepare语句。所以重新写一下：

-(void)InsertRecords
{
    fileMgr = [NSFileManager defaultManager];
    NSString *cruddatabase = [self.GetDocumentDirectory stringByAppendingPathComponent:@"MainDb.sqlite"];
    sqlite3_stmt *stmt;
    sqlite3 *cruddb;

    const char *sql = "Insert into AllDictionary(id, DeleteFlag, TitleBD, Description, PathToDB, ImageURL) VALUES(565,'asasf2','asfas2ff','fggaga2hah','b2bb','aa2aa')";

    if((sqlite3_open([cruddatabase UTF8String], &cruddb)==SQLITE_OK))
    {
        if (sqlite3_prepare(cruddb, sql, -1, &stmt, NULL) ==SQLITE_OK)
        {
            sqlite3_step(stmt);
            sqlite3_finalize(stmt);
        }
        else 
        {
            NSLog(@"Problem with prepare statement: %s", sqlite3_errmsg(cruddb));
        }
        sqlite3_close(cruddb);
    }
    else
    {
       NSLog(@"An error has occured: %s",sqlite3_errmsg(cruddb));
    }
}

无法向数据库SQLite iPhone插入新行

1 个答案: