我使用onmouseover和onmouseout来查看图片,但它不能用于chrome。需要解决这个问题。
脚本是
<script>
var img;
window.onload = function () {
img = document.getElementById ("img");
}
</script>
<img style= "position:absolute;TOP:90px; LEFT:185px;visibility:hidden;"
class="two"
id="img"
src="services/web2.png"
width="800" height="500" alt=""/>
<div class="item home">
<img src="imagess/bg_home.png" alt="" width="199" height="199" class="circle"/>
<a href="#" class="icon"></a>
<h2>IT</h2>
<ul>
<li>
<a href="target4"
onMouseOver="img.style.visibility='visible'; img.src='services/web2.png'"
onMouseOut="img.style.visibility='hidden';">Sales & Service</a>
</li>
<li>
<a href="target5"
onMouseOver="img.style.visibility='visible'; img.src='services/web2.png'"
onMouseOut="img.style.visibility='hidden';">CCTV</a>
</li>
<li>
<a href="target6"
onMouseOver="img.style.visibility='visible'; img.src='services/web2.png'"
onMouseOut="img.style.visibility='hidden';">DVR</a>
</li>
</ul>
</div>
答案 0 :(得分:1)
你使用的是非常突兀的javascript,这简直就是不好的做法。 因此,追踪错误并没有那么多意义。 建议使用jQuery的人非常正确,你会帮自己一个忙 接受这个建议。
直接在DOM元素上使用onMouseOver和其他javascript不再是事情的完成方式。
答案 1 :(得分:0)
分开您的JavaScript
window.onload = function () {
var img = document.getElementById('img'),
links = ['target4', 'target5', 'target6'],
i = links.length, e,
over = function over(){
img.style.visibility='visible';
img.src='services/web2.png';
},
out = function out(){
img.style.visibility='hidden';
};
while( --i >= 0 ){
e = document.getElementById(links[i]);
e.addEventListener('mouseover', over, false);
e.addEventListener('mouseout', out, false);
}
}
来自您的HTML
<img id="img" class="two" src="services/web2.png" alt=""/>
<div class="item home">
<img src="imagess/bg_home.png" alt="" width="199" height="199" class="circle"/>
<a href="#" class="icon"></a>
<h2>IT</h2>
<ul>
<li>
<a id="target4" href="target4">Sales & Service</a>
</li>
<li>
<a id="target5" href="target5">CCTV</a>
</li>
<li>
<a id="target6" href="target6">DVR</a>
</li>
</ul>
</div>
答案 2 :(得分:-1)
你最好将jQuery用于那种适用于所有浏览器的东西。
答案 3 :(得分:-1)
试试这个:
的CSS:
#img {
position:absolute;
top:90px;
left:185px;
visibility:hidden;
}
JS:
$(function(){
var $img = $('#img');
// selector container for image
var $container = $('.item');
$container.find('ul li a')
.bind('mouseover', function(event) {
var target = $(this).attr('href'); //if you need to differentiate
$img
.css('visibility', 'visible')
.attr('src', 'services/web2.png');
})
.bind('mouseout', function(event) {
var target = $(this).attr('href'); //if you need to differentiate
$img
.css('visibility', 'hidden');
})
});
HTML:
<img class="two" id="img" src="services/web2.png" width="800" height="500" alt="" />
<div class="item home">
<img src="imagess/bg_home.png" alt="" width="199" height="199" class="circle"/>
<a href="#" class="icon"></a>
<h2>IT</h2>
<ul>
<li><a href="target4">Sales & Service</a></li>
<li><a href="target5">CCTV</a></li>
<li><a href="target6">DVR</a></li>
</ul>
</div>
答案 4 :(得分:-1)
使用jQuery!
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script src="Scripts/jquery-1.6.2.js" type="text/javascript"></script>
<script type="text/javascript">
$(function () {
$('li a').mouseenter(function () {
$('li a').hide(1);
}).mouseout(function () {
$('li a').show(1);
});
});
</script>
</head>
<body>
<ul>
<li><a id="link" href="http://www.tivo.com/">DVR</a></li>
</ul>
</body>
</html>