Question

    Private Sub LRbtn_Click(sender As Object, e As EventArgs) Handles LRbtn.Click
    OpenFileDialog1.Title = "Please Select a File"
    OpenFileDialog1.ShowDialog()
    Dim filename As String = OpenFileDialog1.FileName
    Dim fs As FileStream = New FileStream(filename, FileMode.Open)
    Dim br As BinaryReader = New BinaryReader(fs)
    br.BaseStream.Seek(verOffset, SeekOrigin.Begin)
    a = br.ReadInt32()
    verLabel.Text = hex2ascii(Hex(a))
    br.Close()
    fs.Close()

End Sub

我打开并二进制读取文件，然后我在给定地址读取4个字节。

例如，转换为十六进制的变量a可能是1163022402 45,52,50,42

将a转换为Hex后，我需要反转该字节以获取42,50,52,45

我是VB的新手，我正在学习它，我该怎么办？三江源！

Answer 1

如果您需要32位只读4个字节，请使用br.ReadBytes然后您可以随意订购

VB.Net以十六进制值反转字节

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