如何将其合并为1个脚本?
$('#tabs, #tabs-1').tabs({
select: function(event, ui){
$("#picture").hide();
}
});
$('#tabs, #tabs-2').tabs({
select: function(event, ui){
$("#picture").hide();
}
});
$('#tabs, #tabs-3').tabs({
select: function(event, ui){
$("#picture").hide();
}
});
$('#tabs, #tabs-4').tabs({
select: function(event, ui){
$("#picture").show();
}
});
答案 0 :(得分:0)
试试这个:
希望它适合原因:)
<强>代码强>
$('#tabs, #tabs-1, #tabs-2, #tabs-3, #tab-4').click(function() {
var num = $(this).attr('class');
//get the number at the end of the class of this particular div
var lastChar = num.substr(num.length - 1)
select: function(event, ui){
if(lastChar == "4")
$("#picture").show();
else
$("#picture").hide();
}
});