我不需要检查业务是开放还是关闭,但我需要按天显示营业时间。
有一些选择:
1 - 商业开放一天一次(样本 - 从10:00到18:30) - 一个 表中的行 2 - 商务开放时间为两天(samlpe - 从10:00到 14:00和15:00至18:30) - 表中有两行 3 - 业务可能 关闭(没有插入行)
这里我的MySql表存放时间。在此示例业务中,(affiliate_id)在0到4天内打开两次,在第5天打开一次,在第6天关闭(此时没有记录)
http://postimage.org/image/yplj4rumj/
我需要在网站上显示它(根据此数据库示例:
0,1,2,3,4 - 开放时间为10:00-14:00和15:00-18:30 5 - 营业时间为10:00-12:00 6 - 关闭
我如何得到如下结果:
http://postimage.org/image/toe53en63/
我尝试用GROUPֹ_CONCAT和LEFT JOIN在a.day = b.day上同一个表进行查询,但没有运气:(
我的查询样本(这是错误的)
SELECT GROUP_CONCAT( DISTINCT CAST( a.day AS CHAR )
ORDER BY a.day ) AS days, DATE_FORMAT( a.time_from, '%H:%i' ) AS f_time_from, DATE_FORMAT( a.time_to, '%H:%i' ) AS f_time_to, DATE_FORMAT( b.time_from, '%H:%i' ) AS f_time_from_s, DATE_FORMAT( b.time_to, '%H:%i' ) AS f_time_to_s
FROM business_affiliate_hours AS a LEFT
JOIN business_affiliate_hours AS b ON a.day = b.day
WHERE a.affiliate_id =57
GROUP BY a.time_from, a.time_to, b.time_from, b.time_to
ORDER BY a.id ASC
这是我的表:
CREATE TABLE IF NOT EXISTS `business_affiliate_hours` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`affiliate_id` int(10) unsigned NOT NULL DEFAULT '0',
`time_from` time NOT NULL,
`time_to` time NOT NULL,
`day` tinyint(1) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`id`)
) ENGINE=MyISAM;
INSERT INTO `business_affiliate_hours` (`id`, `affiliate_id`, `time_from`, `time_to`, `day`) VALUES
(53, 57, '10:00:00', '12:00:00', 5),
(52, 57, '15:00:00', '18:30:00', 4),
(51, 57, '10:00:00', '14:00:00', 4),
(50, 57, '15:00:00', '18:30:00', 3),
(49, 57, '10:00:00', '14:00:00', 3),
(48, 57, '15:00:00', '18:30:00', 2),
(47, 57, '10:00:00', '14:00:00', 2),
(46, 57, '15:00:00', '18:30:00', 1),
(45, 57, '10:00:00', '14:00:00', 1),
(44, 57, '15:00:00', '18:30:00', 0),
(43, 57, '10:00:00', '14:00:00', 0);
每天的营业时间可能会有所不同,所以我希望在相同的营业时间内分组,并获取所有独特的营业时间顺序的天数列表。
需要你的帮助!
很抱歉有图片的链接,我无法将图片上传到此处。
答案 0 :(得分:2)
首先构建每天合并时间的物化表,然后分组:
SELECT GROUP_CONCAT(day ORDER BY day) AS days,
DATE_FORMAT(f1, '%H:%i') AS f_time_from,
DATE_FORMAT(t1, '%H:%i') AS f_time_to,
DATE_FORMAT(f2, '%H:%i') AS f_time_from_s,
DATE_FORMAT(t2, '%H:%i') AS f_time_to_s
FROM (
SELECT day,
MIN(time_from) AS f1,
MIN(time_to ) AS t1,
IF(COUNT(*) > 1, MAX(time_from), NULL) AS f2,
IF(COUNT(*) > 1, MAX(time_to ), NULL) AS t2
FROM business_affiliate_hours
WHERE affiliate_id = 57
GROUP BY day
) t
GROUP BY f1, t1, f2, t2
ORDER BY days
在sqlfiddle上查看。