这将是一个愚蠢的错误。 我得到上面的错误。当用户点击链接时它基本打开一个视图页面,该页面调用需要$ category的类。
<?php
// Initialise the template
require_once "/var/www/template/template.php";
$template = new CHTemplate();
// And create a cid object
require_once "/var/www/Component/DisplayWIPOnLocation.php";
$WIPProgress= new CHWIPProgress();
if(isset($_GET['category'])){
$content .= " <h3> Details for Component : $reference </h3> ";
$bundle = $WIPProgres->GetProducts($_GET['category']);
$reference = $_GET['category'];
// Now show the details
foreach($bundle as $x){
$content .= "
<table>
<tr><th> ProductNumber</th><td>" . $x['ProductNumber'] . "</td>
</tr>
<tr><th> Description </th><td>" . $x['Description'] . "</td></tr>
</table>
<br>";
}
}
$template->SetTag("content", $content);
echo $template->Display();
?>
班级中的对象
public function GetProducts($category) {
$sql = "SELECT DISTINCT `Stock`.`ProductNumber`,`Stock`.`Description`
FROM Stock , TBOM
WHERE `TBOM`.`Component` = '" . $category. "'
AND `Stock`.`ProductNumber` = `TBOM`.`Product`
";
mysql_select_db(DB_DATABASE_NAME, $this->conn);
$result = mysql_query($sql, $this->conn);
$num_rows = mysql_num_rows($result);
//echo "Number of rows : $num_rows";
while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$return[] = $row;
}
return $return;
return $num_rows;
}
答案 0 :(得分:1)
错字:
$WIPProgress= new CHWIPProgress();
^^--- two s's
$bundle = $WIPProgres->GetProducts($_GET['category']);
^--- one S
e.g。你正在调用一个不存在的对象。
答案 1 :(得分:0)
这只是意味着你认为的某个对象是一个对象,不是。
例如:
$bundle = $WIPProgres->GetProducts($_GET['category']); //<< you left off an `s`
这是一个很大的 PEBKAC 错误。