Question

我们有java web应用程序，我们使用spring，hibernate3，我从DB获取记录的实际版本时遇到问题。

以下是代码段：

Class Scheduler
{
    public void scheduleTests(………….)
    {
    .
    .
    .
    TestCase testCase;
    .
    //Updating entity
    getHibernateTemplate ().saveOrUpdate(testCase);
    getHibernateTemplate ().flush();
    .
    .
    .
    Starts new thread
    .
}

Thread run{
    .
    .
    TestCase testCase = getTestCase(testCaseId);
    .
    .
    .
    .
    updateTestCase(testCase);
}

getTestCase(testCaseId)
{
    TestCase testCase = null;
    try
    {                       
        testCase=(TestCase)getHibernateTemplate().get(TestCase.class, testCaseId);
    }
    catch (Exception ex)
    {
       ex.printStackTrace();
    }
    return testCase;
}

updateTestCase(TestCase testCase)
{
    try
    {
       getHibernateTemplate ().saveOrUpdate(testCase);
       getHibernateTemplate ().flush();
    }
    catch (Exception ex)
    {
       ex.printStackTrace();
    }
}

在方法计划测试中，我更改对象TestCase并将其保存到DB中。然后新线程启动，在这个线程的开头我向DB询问DB的实际版本的TestCase。然后执行一些功能，并在TestCase的最终状态更新为DB。

问题是当我运行此场景超过1次。然后发生了奇怪的事情。在线程方法运行中，我从方法getTestCase旧版本的TestCase中获取，然后使用以下异常更新崩溃：

错误

org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:300) - Could not synchronize database state with session
"org.hibernate.StaleObjectStateException: Row was updated or deleted by another transaction (or unsaved-value mapping was incorrect): [at.h3g.portal.db.webshop.WsRcCheck#405]
    at org.hibernate.persister.entity.AbstractEntityPersister.check(AbstractEntityPersister.java:1680)
    at org.hibernate.persister.entity.AbstractEntityPersister.update(AbstractEntityPersister.java:2271)
    at org.hibernate.persister.entity.AbstractEntityPersister.updateOrInsert(AbstractEntityPersister.java:2180)
    at org.hibernate.persister.entity.AbstractEntityPersister.update(AbstractEntityPersister.java:2456)
    at org.hibernate.action.EntityUpdateAction.execute(EntityUpdateAction.java:91)
    at org.hibernate.engine.ActionQueue.execute(ActionQueue.java:248)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:232)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:140)
    at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:297)
    at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:27)
    at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:988)
    at org.springframework.orm.hibernate3.HibernateTemplate$29.doInHibernate(HibernateTemplate.java:815)
    at org.springframework.orm.hibernate3.HibernateTemplate.execute(HibernateTemplate.java:366)
    at org.springframework.
ERROR org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:300) - Could not synchronize database state with session
"org.hibernate.StaleObjectStateException: Row was updated or deleted by another transaction (or unsaved-value mapping was incorrect): [at.h3g.portal.db.webshop.WsRcCheck#405]
    at org.hibernate.persister.entity.AbstractEntityPersister.check(AbstractEntityPersister.java:1680)
    at org.hibernate.persister.entity.AbstractEntityPersister.update(AbstractEntityPersister.java:2271)
    at org.hibernate.persister.entity.AbstractEntityPersister.updateOrInsert(AbstractEntityPersister.java:2180)
    at org.hibernate.persister.entity.AbstractEntityPersister.update(AbstractEntityPersister.java:2456)
    at org.hibernate.action.EntityUpdateAction.execute(EntityUpdateAction.java:91)
    at org.hibernate.engine.ActionQueue.execute(ActionQueue.java:248)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:232)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:140)
    at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:297)
    at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:27)
    at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:988)
    at org.hibernate.impl.SessionImpl.managedFlush(SessionImpl.java:337)
    at org.hibernate.transaction.JDBCTransaction.commit(JDBCTransaction.java:106)
    at org.springframework.orm.hibernate3.HibernateTransactionManager.doCommit(HibernateTransactionManager.java:584)
    at org.springframework.transaction.support.AbstractPlatformTransactionManager.processCommit(AbstractPlatformTransactionManager.java:500)
    at org.springframework.transaction.support.AbstractPlatformTransactionManager.commit(AbstractPlatformTransactionManager.java:473)
    at org.springframework.transaction.interceptor.TransactionAspectSupport.doCommitTransactionAfterReturning(TransactionAspectSupport.java:267)
    at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:106)
    at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:170)

为什么我的旧版TestCase？我能做什么？这是Hibernate和Spring的配置。

在Web.Xml中：

<filter>
    <filter-name>hibernateFilter</filter-name>
    <filter-class>org.springframework.orm.hibernate3.support.OpenSessionInViewFilter</filter-class>
    <init-param>
        <param-name>sessionFactoryBeanName</param-name>
        <param-value>sessionFactory</param-value>
    </init-param>
</filter>

和上下文配置：

<bean id="sessionFactory"
    class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
    <property name="dataSource">
        <ref bean="dataSource" />
    </property>
    <property name="mappingResources">
        <list>
        .
        .
        .
        </list>
    </property>
    <property name="hibernateProperties">
        <props>
            <prop key="hibernate.dialect">
                org.hibernate.dialect.Oracle9Dialect
            </prop>
            <prop key="hibernate.connection.release_mode">
                auto
            </prop>
        </props>
    </property>
</bean>

<bean id="dataSource"
    class="org.springframework.jndi.JndiObjectFactoryBean">
    <property name="jndiName">
        <value>java:comp/env/jdbc/SOMEDATASOURCE</value>
    </property>
</bean>


<bean id="hibernateTemplate"
    class="org.springframework.orm.hibernate3.HibernateTemplate">
    <property name="sessionFactory">
        <ref bean="sessionFactory" />
    </property>
</bean>

<bean id="transactionManager"
    class="org.springframework.orm.hibernate3.HibernateTransactionManager">
    <property name="sessionFactory">
        <ref local="sessionFactory" />
    </property>
</bean>

<bean id="transactionInterceptorTestScheduling"
    class="org.springframework.transaction.interceptor.TransactionInterceptor">
    <property name="transactionManager">
        <ref bean="transactionManager" />
    </property>
    <property name="transactionAttributeSource">
        <value>                 org.company.db.Scheduler.updateTestCase=PROPAGATION_REQUIRES_NEW
        </value>
    </property>
</bean>

我想补充一点，在那个时候只创建了一个线程，没有其他任何东西可以访问数据库中的TestCase数据。唯一的问题是getTestCase返回旧版本的TestCase记录，我现在不知道原因。

感谢您的建议。

Answer 1

问题是hibernate会话是否与当前线程有关。所以一个解决方案是不使用线程，或者应该创建事务拦截器，它将负责线程的会话。有关Spring How to get bean with prototype scope from ProxyFactoryBean

的更多信息，请参阅

Hibernate get方法在线程中返回旧版本的记录

1 个答案: