针对XSD进行XML验证时出错

时间:2012-11-09 07:33:04

标签: java xml xsd

我在java中编写了以下代码进行验证,但它总是返回true。即使我修改XML并使其与XSD不兼容,它仍然返回true。请看一下。

public static boolean isValidXML(String filePath,String xsdFile){
    boolean bValue = true;
    SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
    try {
        DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
        documentBuilderFactory.setNamespaceAware(true);
        DocumentBuilder parser = documentBuilderFactory.newDocumentBuilder();
        Document document = parser.parse(new File(filePath));

        Schema schema = schemaFactory.newSchema(new File(xsdFile));
        Validator validator = schema.newValidator();

        final List<SAXParseException> exceptions = new LinkedList<SAXParseException>();
        validator.setErrorHandler(new ErrorHandler()
        {
          public void warning(SAXParseException exception) throws SAXException
          {
            exceptions.add(exception);
          }

          public void fatalError(SAXParseException exception) throws SAXException
          {
            exceptions.add(exception);
          }

          public void error(SAXParseException exception) throws SAXException
          {
            exceptions.add(exception);
          }
        });
        validator.validate(new DOMSource(document));
    } catch (SAXException e) {
        bValue = false;
        logger.error("Error while Validating the XML."+e);
        e.printStackTrace();
    } catch (ParserConfigurationException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    return bValue;
}

1 个答案:

答案 0 :(得分:2)

ErrorHandler界面实施中,请尝试以下操作:

而不是

exceptions.add(exception);

执行以下操作

throw exception;

您的实施可能会消耗验证异常。您还可以检查exceptions并根据其内容返回。为什么要填写以后从未使用的列表?