当它运行时,如果忽略我的if条件,它会跳过它。为什么和修复?

时间:2012-11-08 23:42:54

标签: bash shell

我的代码在这里。尽管如此,你不必担心第二个问题。它恰好与玩家2相同。

#!/bin/bash
#this is a game that is two player and it is a race to get to 
#100 before the other player

echo "Player 1 name?"
read p1
echo "Player 2 name?"
read p2
echo "Okay $p1 and $p2. $p1 will go first"
p1s=0
p2s=0
pt=1

while [ $pt == 1 ]; do
echo "roll or stay"
read choice

if [ $choice == r ]; then

die=$(($RANDOM%6+1))

elif [ $die -eq 1 ]; then
p1s=$(echo "$p1s-$count" |bc)
echo "You rolled a 1. Your score is $p1s"
echo "$p2 turn now."
sleep 1
count=0
pt=2

elif [ $die > 1 ]; then
p1s=$(echo "$p1s+$die" |bc)
count=$(echo "$count+$die" |bc)
echo "You rolled a $die. Your score is $p1s"
pt=1

else

if [ $choice == s ]; then
echo "Okay $p1 your score is $p1s"
echo "$p2 turn now"
sleep 1
count=0
pt=2

else

pt=1

fi
fi

if [ $p1s > 99 ]; then
echo "$p1 won. $p2 lost"
echo "would you like to play again?"
read again
elif [ $again == yes ]; then
echo "Okay one second."
sleep 1
clear
bash num.sh
elif [ $again == no ]; then
echo "ok going back to the games directory then"
sleep 1
bash games.sh

fi

done

while [ $pt == 2 ]; do
echo "roll or stay"
read choice
if [ $choice == r ]; then

die=$(($RANDOM%6+1))

elif [ $die -eq 1 ]; then
p1s=$(echo "$p2s-$count" |bc)
echo "You rolled a 1. Your score is $p2s"
echo "$p1 turn now."
sleep 1
count=0
pt=2

elif [ $die > 1 ]; then
p1s=$(echo "$p2s+$die" |bc)
count=$(echo "$count+$die" |bc)
echo "You rolled a $die. Your score is $p2s"
pt=1

else

if [ $choice == s ]; then
echo "Okay $p1 your score is $p2s"
echo "$p1 turn now"
sleep 1
count=0
pt=2

else

pt=2

fi
fi

if [ $p2s > 99 ]; then
echo "$p2 won. $p1 lost"
echo "would you like to play again?"
read again
elif [ $again == yes ]; then
echo "Okay one second."
sleep 1
clear
bash num.sh
elif [ $again == no ]; then
echo "ok going back to the games directory then"
sleep 1
bash games.sh

fi

done

运行后会发生什么?

Player 1 name?
name1
Player 2 name?
name2
Okay name1 and name2. name1 will go first
roll or stay
r
name1 won. name2 lost
would you like to play again?

它应该滚动,你得到一个随机数,如果一个然后该轮的分数被删除并转到下一个玩家。如果您掷出2-6则会增加该回合分数。如果你留下,那么你保存你的分数,每轮得分加起来直到一个玩家得到100分。

0 个答案:

没有答案