什么是SQL查询的mongoose等价物

Question

select _id from project where projectName = '***' order by viewCount desc limit 5

我仍然是mongoose的新手并且有一点中间的SQL理解，这是我的尝试，因为我正在尝试检索已排序的返回的ObjectId

ProjectModel.find({id}).sort({viewCount: -1}).limit(5).exec( 
    function(err, projects) {
        ...
    }
);

Answer 1

ProjectModel.find({projectName: '***'}, ["_id"]).sort({viewCount: -1}).limit(5).exec( 
    function(err, projects) {
        ...
    }
);