Question

我的网络应用程序需要从我的数据库中获取的信息，我只能为整个数据库生成，其中包含许多填充全新表的查询。任何人都可以向我建议一个查询返回与此填充表完全相同的结果吗？

首先，这是两个有信息的表。

CREATE OR REPLACE TABLE AS_Event(
    AS_Id   INT,
    geneAbsentId    VARCHAR(15),
    genePresentId   VARCHAR(15),
)ENGINE=INNODB;

CREATE OR REPLACE TABLE AS_ChoiceSupport(
    AS_Id   INT,
    GeneId  VARCHAR(15),
    ESTId   VARCHAR(20),
    LibraryId   INT,
)ENGINE=INNODB;

我已将其简化为我们需要的信息。 geneAbsentId和genePresentId（或AS_Choice）指向与AS_ChoiceSupport中的GeneId相同的表。每个事件中的每个AS_Choice都可以具有＆gt; = 0 AS_ChoiceSupport行。

现在，这是我正在创建的新表，但我需要它来代替单个查询。

CREATE TABLE AS_Support_Count(
    AS_Id   INT,
    gaCount INT,
    gpCount  INT,
    PRIMARY KEY(AS_Id),
    FOREIGN KEY(AS_Id) REFERENCES AS_Event(AS_Id) ON UPDATE CASCADE ON DELETE CASCADE
)ENGINE=INNODB;

INSERT INTO AS_Support_Count(AS_Id) SELECT AS_Id FROM AS_Event

CREATE OR REPLACE VIEW TEMP AS SELECT e.AS_Id, COUNT(e.genePresentId) AS gpCount FROM AS_Event e, AS_ChoiceSupport c WHERE (e.AS_Id = c.AS_Id) AND e.genePresentId = c.GeneId GROUP BY e.AS_Id

UPDATE AS_Support_Count a, TEMP t
SET a.gpCount = t.gpCount
WHERE a.AS_Id = t.AS_Id

UPDATE AS_Support_Count
SET gpCount = 0
WHERE gpCount IS NULL

CREATE OR REPLACE VIEW TEMP AS SELECT e.AS_Id, COUNT(e.geneAbsentId) AS gaCount FROM AS_Event e, AS_ChoiceSupport c WHERE (e.AS_Id = c.AS_Id) AND e.geneAbsentId = c.GeneId GROUP BY e.AS_Id

UPDATE AS_Support_Count a, TEMP t
SET a.gaCount = t.gaCount
WHERE a.AS_Id = t.AS_Id

UPDATE AS_Support_Count
SET gaCount = 0
WHERE gaCount IS NULL

我需要将其缩写为单个查询的原因是我有时需要根据库ID获取事件的信息。即我需要知道AS_Event x有多少来自LibraryId的AS_ChoiceSupports。

我知道这是一个很大的问题所以我会将PokerStars的5美元转移给给我正确答案的人。

Answer 1

我发现了如何从在线教程中转换数据 link text

这是我提出的查询

SELECT
    COUNT(CASE WHEN e.genePresentId = c.GeneId THEN c.LibraryId ELSE NULL END) AS 'gpCount',
    COUNT(CASE WHEN e.geneAbsentId = c.GeneId THEN c.LibraryId ELSE NULL END) AS 'gaCount'
FROM
    AS_Event e, AS_ChoiceSupport c
WHERE e.AS_Id = c.AS_Id AND c.LibraryId = ? <sql:param value="${LibraryId}"/>
GROUP BY
    c.AS_Id
ORDER BY
    e.AS_Id

获得PokerStars扑克之星奖。但是，如果您有更好的答案，请为社区提供。

Answer 2

这是否与AS_Support_Count中的select *产生相同的结果？

SELECT e.AS_Id
     , COUNT(e.geneAbsentId) as gaGount
     , COUNT(e.GenePresentId) as gpCount
  FROM AS_Event e
  JOIN AS_ChoiceSupport c
    ON c.AS_Id = e.AS_Id
   AND c.GeneId IN (e.geneAbesntId, e.genePresentId)
GROUP
    BY e.AS_Id

多查询SQL简化为一个结果

2 个答案: