java中的java超出范围

Question

这段代码很有效但很难看：

for ( int i = 0, l=1; i < word.length() && l < word.length(); i++, l++) {  
    char c = word.charAt(i);
    j = (int) c;
    char nextRank = word.charAt(l);
    k = (int) nextRank;
} 

我想把他变成这样的东西：

for (int i = 0; i < word.length(); i++) {  
    char c = word.charAt(i);
    j = (int) c;
    char nextRank = word.charAt(i+1);
    k = (int) nextRank;
} 

这一个返回错误：String index out of range。我理解为什么：当谈到最后一个字母时，＆＃34; char nextRank = word.charAt（i + 1）;＆＃34;没有什么可做的。

但我不知道如何解决这个问题！

Answer 1

从i

开始1

for (int i = 1; i < word.length(); i++) {  
        char c = word.charAt(i-1);
        j = (int) c;
        char nextRank = word.charAt(i);
        k = (int) nextRank;
    } 

Answer 2

病人：“当我在这种情况下这样做时会感到疼痛”

医生：“好吧，那么如果满足这个条件，就不要这样做”

if(i+1 < word.length)
{
    char nextRank = word.charAt(i+1);
    ...

Answer 3

怎么样

for (int i = 0; i < word.length() - 1; i++) {  

Answer 4

int length = word.length() - 1;
for (int i = 0; i < length; i++) {
    char c = word.charAt(i);
    j = (int) c;
    char nextRank = word.charAt(i + 1);
    k = (int) nextRank;
}

Answer 5

将i的限制减少1

for (int i = 0; i < word.length()-1; i++) {  
            char c = word.charAt(i);
            j = (int) c;
            char nextRank = word.charAt(i+1);
            k = (int) nextRank;
        } 

Answer 6

你只需要从0循环到word.length（）-1。

        for (int i = 0; i < word.length() - 1; i++) {  
            char c = word.charAt(i);
            j = (int) c;
            char nextRank = word.charAt(i+1);
            k = (int) nextRank;
        }