Question

我有一个NSMutableArray有70个对象，它们是NSMutableDictionary，在每个字典里面我有2个值：“distance”和“indexPath”。我想将NSMutableArray从小距离排序到最大距离。使用我粘贴的代码后，距离以KM为单位，数组看起来像这样：

NSSortDescriptor *descriptor = [NSSortDescriptor sortDescriptorWithKey:@"distance" ascending:YES];
[branchDistance sortedArrayUsingDescriptors:[NSArray arrayWithObjects:descriptor,nil]];

这是此方法的结果：

(lldb) po [branchDistance objectAtIndex:0]
(id) $1 = 0x0d6ac240 {
    "<NSIndexPath 0xd6cf180> 1 indexes [0]" = indexPath;
    "8.078547" = distance;
}
(lldb) po [branchDistance objectAtIndex:1]
(id) $2 = 0x0d6a64a0 {
    "<NSIndexPath 0xd6cf3b0> 1 indexes [1]" = indexPath;
    "45.044069" = distance;
}
(lldb) po [bran(lldb) po [branchDistance objectAtIndex:2]
(id) $4 = 0x0d6cf550 {
    "<NSIndexPath 0xd69b3f0> 1 indexes [2]" = indexPath;
    "9.992081" = distance;
}
(lldb) po [branchDistance objectAtIndex:3]
(id) $5 = 0x0d6cf750 {
    "283.356727" = distance;
    "<NSIndexPath 0xd6cf480> 1 indexes [3]" = indexPath;
}

我希望使用NSMutableArray内的“距离”键值，将NSMutableDictionary从小数字排序为大数字。我从网络和stackoverflow尝试了几段代码，但是找不到对我有用的东西。

请帮助我！

谢谢！

Answer 1

我假设距离值使用NSNumber对象存储在词典中：

NSArray *sortedArray = [branchDistance sortedArrayUsingComparator:^(id obj1, id obj2) {
    NSNumber *distance1 = [(NSDictionary *)obj1 objectForKey:@"distance"];
    NSNumber *distance2 = [(NSDictionary *)obj2 objectForKey:@"distance"];
    return [distance1 compare:distance2];
}];

通过字典键的值对包含NSMutableDictionary的NSMutableArray进行排序

1 个答案: