Question

 var g_Year = [
         { Year: "2011" },
         { Year: "2011" },
         { Year: "2010" },
         { Year: "2012" },
         { Year: "2011" },
         { Year: "2012" }
];
fxnDrop = function () {
        $.each(g_Year , function (index, Ele) {
            var iYear = g_Year [index].Year,
                sHtmlYear = '<option value="' + iYear + '">' + iYear + '</option>';
            $("#DropDown_Year").each(function (index, Ele) {
                $("#DropDown_Year").append(sHtmlYear);
                if (Ele.value != iYear) {
                    $("#DropDown_Year").remove(sHtmlYear);
                }
            });
        });
}

这里我有多年，我的目标是在下拉框中只显示特定年份一次。例如：2011年必须在下拉框中只显示一次。任何人都可以帮助我做到这一点。我在Dropbox中获得了多个2011年值。

Answer 1

试试此代码

var fxnDrop = function() {
    var yearsArray = [];
    $.each(g_Year, function(index) { 
        if($.inArray(+g_Year[index].Year , yearsArray) == -1){
            yearsArray.push(+g_Year[index].Year);
        }
    });
    yearsArray.sort();
    var sHtmlYear = '';
    $.each(yearsArray , function(i){
        sHtmlYear += '<option value="'+ yearsArray[i] +'">' 
                         + yearsArray[i]  + '</option>'; 
    });
     $("#DropDown_Year").append(sHtmlYear);
};

fxnDrop();

<强> Check Fiddle

Answer 2

你可以使用Jquery.inArray()函数：对于exe： -

  var categories=[];
         if ($.inArray(value.category, categories)==-1){
        categories.push(value.category);
        }

categories将保留您需要的唯一类别的更新
[SEE LIVE DEMO][2]

Answer 3

尝试这个..使用@pranav

提到的Jquery.inArray（）

var yeararray= [];

fxnDrop = function () {
    $.each(g_Year , function (index, Ele) {
       if ($.inArray(Ele.Year, yeararray)==-1) {
        var iYear = g_Year [index].Year,
        sHtmlYear = '<option value="' + iYear + '">' + iYear + '</option>';
        $("#DropDown_Year").each(function (index, Ele) {
            $("#DropDown_Year").append(sHtmlYear);
            if (Ele.value != iYear) {
                $("#DropDown_Year").remove(sHtmlYear);
            }
        });
          yeararray.push(Ele.Year);
       }
    });
}

Answer 4

var g_Year = [
         { Year: "2011" },
         { Year: "2011" },
         { Year: "2010" },
         { Year: "2012" },
         { Year: "2011" },
         { Year: "2012" }
];
g_Year.sort(function(o1, o2){return o1.Year > o2.Year} );

// use reduce function
var uniqueG_Year = g_Year.reduce(function(previousValue, currentValue, index, array){
  if(previousValue.length == 0 || previousValue[previousValue.length-1].Year != currentValue.Year)
    previousValue.push(currentValue);
  return previousValue;
}, []);

// or simply use filter
var uniqueG_YearFiltered = g_Year.filter(function(element, index, array){
  return (index == 0 || array[index-1].Year != element.Year)
});

将json值插入下拉框

4 个答案: