我有一组相对于复合材料的x / y坐标,如何找到那些coords落入的小部件?
答案 0 :(得分:5)
这很难看,但你可以做这样的功能:
public Control getControl(Composite composite, int x, int y)
{
Control control = null;
Control[] children = composite.getChildren()
if (children.length == 0)
control = composite;
else
for (Control tmp : children) {
// The check below will not work because x, y and the control's bounds could be
// relative to different parents... Better to convert all coordinates to display
// by using Control.toDisplay() and then compare below
if (tmp.getBounds().contains(x, y))
{
if (control instanceof Composite)
control = getControl(tmp, x, y);
else
control = tmp;
break;
}
}
return control;
}
如果使用MouseListener获取坐标,则只需使用:
event.getSource();