Question

好的，我问过如何将Linq查询结果作为XML返回，我得到了答案here。

但是有一个小问题：结果不会在XML中逻辑分组。例如：

XElement xml = new XElement("States",
  from s in MyStates
  from cy in s.Counties
  from c in cy.Cities
  where s.Code == "NY"
  orderby s.Code, cy.Name, c.Name
  select new XElement("State",
    new XAttribute("Code", s.Code),
    new XAttribute("Name", s.Name),
    new XElement("County",
      new XAttribute("Name", cy.Name),
      new XElement("City",
        new XAttribute("Name", c.Name)
      )
    )
  )
);

Console.WriteLine(xml);

输出格式为：

<State Code="NY" Name="New York ">
  <County Name="WYOMING">
    <City Name="WARSAW" />
  </County>
</State>
<State Code="NY" Name="New York ">
  <County Name="WYOMING">
    <City Name="WYOMING" />
  </County>
</State>
<State Code="NY" Name="New York ">
  <County Name="YATES">
    <City Name="BELLONA" />
  </County>
</State>
<State Code="NY" Name="New York ">
  <County Name="YATES">
    <City Name="MIDDLESEX" />
  </County>
</State>
<State Code="NY" Name="New York ">
  <County Name="YATES">
    <City Name="PENN YAN" />
  </County>
</State>
<State Code="NY" Name="New York ">
  <County Name="YATES">
    <City Name="RUSHVILLE" />
  </County>
</State>

而不是：

<State Code="NY" Name="New York ">
  <County Name="WYOMING">
    <City Name="WARSAW" />
    <City Name="WYOMING" />
  </County>
  <County Name="YATES">
    <City Name="BELLONA" />
    <City Name="MIDDLESEX" />
    <City Name="PENN YAN" />
    <City Name="RUSHVILLE" />
  </County>
</State>

如何根据需要显示结果？

Answer 1

为了获得您想要的结果，我相信您必须将LINQ嵌套到XML查询中。在外部查询中，您将必须查询不同的状态...然后是内部查询以获取该状态的县...然后是另一个内部查询来获取该县的城市。

Linq / XML：在XML元素中正确分组结果

1 个答案: