Question

我正在使用python和simplekml创建器创建kml文件。由于某种原因，它会创建两个kml文件，而不会创建第三个。数据似乎很好。这是代码：

times=open("E:\\Python\Copyofresttable.csv","r")
import time
import csv
import simplekml
from time import strftime, localtime
dayoftheweekvariable = strftime("%A", localtime())
print dayoftheweekvariable
kml = simplekml.Kml()


if dayoftheweekvariable == "Monday":
     for line in times:
        a = line.split(',')
        if a[2] == "Monday":
            print a[5]

if dayoftheweekvariable == "Tuesday":
     for line in times:
        a = line.split(',')
        if a[2] == "Tuesday":
            print a[5]

if dayoftheweekvariable == "Wednesday":
    for line in times:
        a = line.split(',')

        if a[1]== "Iron Hill" and a[2] =="Wednesday":
            kml.newpoint(name="Iron Hill", coords=[(-75.605507,39.960504)], description=a[5])
            kml.save("pythonmap.kml")
            print "Creating KML"

        if a[1]== "Side Bar and Resturant" and a[2] =="Wednesday":
            kml.newpoint(name="Side Bar and Resturant", coords=[(-75.604805,39.960591)], description=a[5])
            kml.save("pythonmap.kml")
            print "Creating KML"

        if a[1]== "Barnaby's" and a[2] =="Wednesday":
            kml.newpoint(name="Barnaby's", coords=[(-75.604049,39.959488)], description=a[5])
            kml.save("pythonmap.kml")
            print "Creating KML"

显然在星期三晚上测试了这个...至于最后三个if语句，无论我把它们放入什么顺序，它都会为Iron Hill和Barnaby创造一个kml而不是侧栏。这是它返回的结果：

Wednesday
Creating KML
Creating KML

Traceback (most recent call last):
  File "C:/Users/75IV740906/Desktop/py117", line 26, in <module>
    if a[1]== "Iron Hill" and a[2] =="Wednesday":
IndexError: list index out of range

错误消息会调出if if语句在顶部的内容。我很难过。希望我的问题有意义（为什么它给我这个错误信息，只要创建两个kml，无论if语句的顺序是什么）

Answer 1

更改

times=open("E:\\Python\Copyofresttable.csv","r")

为：

times=open("E:\\Python\Copyofresttable.csv","r").read()

在第一行

添加

print('#Times: {0}'.format(len(times.split())))

确保你有足够的线......

<强>更新：

你的回溯（在评论中）显示你的（第一个？！）dayoftheweek似乎是一个星期三，这就是你的前两个ifs被忽略的原因。然后看起来您的列表a没有足够的条目。

您可以使用print("# a: {0}".format(len(a)))

检查该假设

因此，如果您有少于3个条目a[2]==必须失败，因为list index out of range; - ）

啊，我一开始没有正确地阅读你的问题。如果每个第一个if语句都抛出异常，那就更有意义了......

更新2： 顺便说一下：你应该将你的for line in times:循环重新排列成一种不太冗余的方式，例如：

lines=open("E:\\Python\Copyofresttable.csv","r").readlines()
...
for line in lines:
    a = line.split(',')
    if a[2] == "Monday" == dayoftheweek:
        ...
    elif a[2] == "Tuesday" == dayoftheweek:
        ...
    elif a[1]== "Iron Hill" and a[2] =="Wednesday" == dayoftheweek:
        ...

更新3：

如果省略某些行，你可以通过做类似的事情来“欺骗”一点：

a = line.split(',')
if len(a) < 6:
   continue   # ignores the rest of the loop and jumps stright to the next iteration

在使用python创建kmls时遇到问题

1 个答案: