Question

我使用以下代码获取地址簿中所有联系人的手机号码（即第一个电话号码）。我想将所有这些号码存储到NSArray

中

self.dataSource = [[NSMutableArray alloc]init]; // dataSouce is delared in .h file
ABAddressBookRef addressBook = ABAddressBookCreate();
NSMutableArray *allPeople = (__bridge NSMutableArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);
int nPeople = ABAddressBookGetPersonCount(addressBook);

for(int i=0; i < nPeople; i++ ){
    ABRecordRef person = (__bridge ABRecordRef)([allPeople objectAtIndex:i]);
    NSString *name = @"";

    if(ABRecordCopyValue(person, kABPersonFirstNameProperty) != NULL)
        name = [[NSString stringWithFormat:@"%@", ABRecordCopyValue(person, kABPersonFirstNameProperty)] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
    [_dataSource addObject: name];

    ABMultiValueRef phoneNumberProperty = ABRecordCopyValue(person, kABPersonPhoneProperty);
    _phoneNumbers = (__bridge NSArray*)ABMultiValueCopyValueAtIndex(phoneNumberProperty, 0);
    CFRelease(phoneNumberProperty);
    NSLog(@"Phone numbers = %@", _phoneNumbers);
}

但是当我使用NSLog(@"Phone numbers = %@", _phoneNumbers);时，输出结果为

2012-11-07 15:31:06.116 contacts[4938:12b03] Phone numbers = 1 (800) 111-1111
2012-11-07 15:31:06.117 contacts[4938:12b03] Phone numbers = (222) 355-5668
2012-11-07 15:31:06.118 contacts[4938:12b03] Phone numbers = (910) 192-0192

我想要NSArray中的输出

Phone numbers = ( 
"1 (800) 111-1111",
"(222) 355-5668",
"(910) 192-0192" 
)

我该怎么做？

Answer 1

你能做到就像这样

 self.dataSource = [[NSMutableArray alloc]init]; // dataSouce is delared in .h file
    ABAddressBookRef addressBook = ABAddressBookCreate();
    NSMutableArray *allPeople = (__bridge NSMutableArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);
    int nPeople = ABAddressBookGetPersonCount(addressBook);

    NSMutableArray *arrContacts = [[NSMutableArray alloc] init];

    for(int i=0; i < nPeople; i++ ){
        ABRecordRef person = (__bridge ABRecordRef)([allPeople objectAtIndex:i]);
        NSString *name = @"";

        if(ABRecordCopyValue(person, kABPersonFirstNameProperty) != NULL)
            name = [[NSString stringWithFormat:@"%@", ABRecordCopyValue(person, kABPersonFirstNameProperty)] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
        [_dataSource addObject: name];

        ABMultiValueRef phoneNumberProperty = ABRecordCopyValue(person, kABPersonPhoneProperty);
        _phoneNumbers = (__bridge NSArray*)ABMultiValueCopyValueAtIndex(phoneNumberProperty, 0);
        CFRelease(phoneNumberProperty);
        NSLog(@"Phone numbers = %@", _phoneNumbers);
        [arrContacts addObject:_phoneNumbers];
    }
    NSLog(@"Phone numbers : %@",arrContacts);

Answer 2

我是通过谷歌发现的，并且使用这个地址簿代码作为示例，但发现了一个错误，我对其他人来说是正确的。

使用ABMultiValueCopyValueAtIndex时，它会返回CFTypeRef类型。该函数只获取该索引处的电话号码（在这种情况下为索引0），如果电话号码是CFStringRef，则不应该将其转换为NSArray*。< / p>

ABMultiValueCopyArrayOfAllValues将是正确调用以获取存储在联系人中的所有电话号码的数组。这可以存储到数组中并像Sarafaraz一样记录下来。

NSArray *_phoneNumbers = (__bridge NSArray*)ABMultiValueCopyArrayOfAllValues(phoneNumberProperty);

如果您只是想获得第一个电话号码，您可以这样做：

CFStringRef phoneNumberRef = ABMultiValueCopyValueAtIndex(phoneNumberProperty, 0);
NSString *phoneString = (__bridge NSString*)phoneNumberRef;

从地址簿中获取电话号码

2 个答案: