我有一个包含以下表格的WordPress数据库
帖子
+--------------+
| Field |
+--------------+
| ID |
| post_author |
| post_title |
| post_type |
+--------------+
postmeta
+--------------+
| Field |
+--------------+
| meta_id |
| post_id |
| meta_key |
| meta_value |
+--------------+
并拥有meta_key
值latitude
和longitude
如何编写SQL以显示latitude
和longitude
作为结果列名称?
+--------------+
| Field |
+--------------+
| ID |
| post_author |
| post_title |
| latitude |
| longitude |
+--------------+
以下查询是我的出发点
SELECT ID, post_title, meta_key, meta_value FROM `wp_posts`
LEFT JOIN `wp_postmeta` on ID=post_id
WHERE post_type='place' AND (meta_key='latitude' OR meta_key='longitude')
ORDER BY ID ASC
答案 0 :(得分:3)
听起来您想要PIVOT
latitude
和longitude
值PIVOT
。不幸的是,MySQL没有CASE
函数,但您可以使用带有SELECT p.ID,
p.post_title,
p.post_author,
max(case when pm.meta_key='latitude' then pm.meta_value end) latitude,
max(case when pm.meta_key='longitude' then pm.meta_value end) longitude
FROM `wp_posts` p
LEFT JOIN `wp_postmeta` pm
on p.ID=pm.post_id
WHERE p.post_type='place'
AND (pm.meta_key='latitude' OR pm.meta_key='longitude')
GROUP BY p.ID, p.post_title, p.post_author
ORDER BY p.ID ASC
语句的聚合函数来复制它:
{{1}}
答案 1 :(得分:0)
您可以使用以下内容:
SELECT
wp_posts.ID,
wp_posts.post_title,
wp_post_1.meta_value as latitude,
wp_post_2.meta_value as longitude
FROM
wp_posts
LEFT JOIN wp_postmeta wp_post_1
ON wp_posts.ID=wp_post_1.post_id and wp_post_1.meta_key = 'latitude'
LEFT JOIN wp_postmeta wp_post_2
ON wp_posts.ID=wp_post_2.post_id and wp_post_2.meta_key = 'longitude'
WHERE post_type='place'
ORDER BY ID ASC